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yarga [219]
3 years ago
5

The acceleration of an object can be described by the equation a=2d/t^2, where a is acceleration d is the distance, and t is tim

e. suppose an object accelerates for a distance of 15 meters. which of the following equations relates the time to the acceleration?
Physics
1 answer:
kherson [118]3 years ago
8 0
As described above, the acceleration of the object is given by the equation, a=2d/t^2. If the object accelerates at a distance of 15 meters, then it can be said that the acceleration will be doubled as compared to the previous with the same time squared. Time can be related by the equation,
t=sqrt of 30/a
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Answer:

The weight of the girl = 1045.86 kg/m³

Explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

⇒ D₁/D₂ = W/U............................... Equation 1.

Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

<em>Given: D₂ = 1000 kg/m³ , W = 509.45 N, U = lost in weight = weight in air - weight in water = 509.45 - 22.34 = 487.11 N</em>

<em>Substituting these values into equation 2</em>

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

Thus the weight of the girl = 1045.86 kg/m³

<em></em>

7 0
4 years ago
(10 pt)
Lubov Fominskaja [6]

Answer:

C

Explanation:

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8 0
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3. A Japanese bullet train slows from a speed of 50 m/sec to a speed of 40 m/sec in 500m.
Triss [41]

Answer:

-0.9 m/s²

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In this case, you can't ignore friction because the disk wouldn't roll without it.

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(You could probably argue that by Newton's 3rd Law there should be some opposing torque, but I think that's outside of the scope of this problem.)

Hopefully this helps clear up the misunderstanding for you.

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Ierofanga [76]
Mhm nice question gimmie a sec
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