The temperature when Spencer arrived at school was a very chilly

What is the distance between (-6,0) and (5,3)?

Dmitriy789 [7]

Answer:

$\sqrt{130}$ or 11.4

Step-by-step explanation:

Use the distance formula:

d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

Plug in the points:

d = $\sqrt{(-6 - 5)^2 + (0 - 3)^2}$

Simplify:

d = $\sqrt{(-11)^2 + (-3)^2}$

d = $\sqrt{121 + 9}$

d = $\sqrt{130}$

= approximately 11.4

So, the distance is $\sqrt{130}$ or approx. 11.4

6 0

3 years ago

Decrease <br>133 in the ratio 7:2

love history [14]

Answer:

38

Step-by-step explanation

2/7× 133=38

6 0

3 years ago

Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.

hodyreva [135]

Answer:

Step-by-step explanation:

3. Use Cosine law to find the length of the unknown side (PR)

q² = p² + r² - 2prCos Q

q is the opposite side of ∠Q;

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² - 2* 33*67 Cos 19°

= 1089 + 4489 - 4422 * 0.95

= 1089 + 4489 - 4200.9

= 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

$\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}$

Sin P = 0.3

$P = Sin^{-1} 0.3\\$

P = 17.5°

∠R = 180 - (19 + 17.5)

= 143.5°

6 0

2 years ago

Store A uses the newsvendor model to manage its inventory. Demand for its product is normally distributed with a mean of 500 and

ra1l [238]

Answer:

$P(X$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the Demand for its product on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=500,\sigma=300)$