Answer:
On the left side of calcium atom.
Explanation:
There are two dots are present on the left side of calcium atom which represents the unpaired electrons present in the outermost shell. This structure is presented by Lewis in order to show the number of unpaired electrons in the atom. if the calcium atom loses these two electron during a chemical reaction so the two dots disappear and the calcium atom is now stable.
Ionization energy increases from left to right in the row and from bottom to top in a column. Also as we get closer to the nucleus it would be harder to take electrons out. B (atomic #5) has 2 layers of electron 2 and 3 atom in each layer. P has 15 so it would be 2,8 and 5 respectively. Ca is 20 so 2,8,8,2 and Zn is 30 and it would be 2,18,8,2.
For energy between second and third ionization we are looking at taking out the 3rd electron. B already has 3 electron in the first layer so its easy to take them all. P has 5 in the last layer so again easy. But when we look at Ca and Zn after the 2nd electron (in the last layer) we should change the layer go one layer inside. So this needs more energy. To pick between Zn and Ca (they are in the same row) I mentioned earlier that in one row as we go to the right ionization energy increases so the answer is Zn.
Answer:
mass is 4.57 g
Explanation:
Ca(OH)₂ solution consists of Ca(OH)₂ solute molecules and solvent and we are asked to find the mass of Ca(OH)₂ in the solution
number of moles of Ca(OH)₂ is - 0.0787 mol
molar mass of Ca(OH)₂ is - 58.093 g/mol
we can use the following equation
number of moles = mass of Ca(OH)₂ / molar mass of Ca(OH)₂
rearranging the equation
mass of Ca(OH)₂ = number of moles x molar mass
mass = 0.0787 mol x 58.093 g/mol = 4.57 g
mass of Ca(OH)₂ is 4.57 g
Theory. maybe hypothesis.
Answer:
Explanation:
A. Na = 23 g/m Cl = 35.5 g/m NaCl = 58.5 g/m
10g / 58.5 g/m = .17 mole
.17 mole/ 2.0 L = 0.086 m/L = 0.086 Molar
B. 342 g/m 52.5/342 =0.15 mole 0.15 mole/1.0 L = 0.15 Molar
C. Al2(SO4)3== 342 g/m 120/342 = 0.35 mole 0.35 m/10.L 0.035 Molar
D caffeine = 194 g/m 1.75/ 194 = 0.009 mole 0.009/0.100 L 0.09 Molar
