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vazorg [7]
3 years ago
12

An object with a mass of 0.225 kg and density of 2.89 g/cm3 measures 34mm in length and 46mm in width. what is the hight of the

object?
Chemistry
1 answer:
Hitman42 [59]3 years ago
8 0
4.15760869565 cm or 41.5760869565
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What is the maximum number of hydrogen bonds that can be formed in a sample containing 1.0 mol (NÅ molecules) liquid HF? Compare
MAVERICK [17]

Answer:

Explanation:

In one mole of liquid HF , no of molecules is 6.02 x 10²³.

Each molecule forms two hydrogen bonds on an average so no of hydrogen bonds per mol ih HF is

2 x  6.02 x 10²³.

= 12.04 x 10²³ .

In water no of hydrogen bonds per molecule of water is 4 . So in one mole of water no of hydrogen bonds is

4 x 6.02 x 10²³.

= 24.08 x 10²³ .

3 0
3 years ago
Which of the protist is the most complex organism ?
Evgen [1.6K]

Which of the protist is the most complex organism ?  

A) paramecium

<u>B) amoeba </u>

C) Euglena

D) Volvox

7 0
3 years ago
How many moles of potassium are contained in 150 g of potassium
BaLLatris [955]

Answer:

150 g of potassium contained 3.8 moles of potassium.

Explanation:

Given data:

Mass of potassium = 150 g

Moles of potassium = ?

Solution:

Number of moles = mass/ molar mass

Molar mass of potassium = 39 g/mol

Now we will put the values in formula:

Number of moles = mass/ molar mass

Number of moles = 150 g/ 39 g/mol

Number of moles = 3.8 mol

150 g of potassium contained 3.8 moles of potassium.

3 0
4 years ago
In which substance are the particles close together and slowly moving past each other? Air, Ice, Steam or Water?
damaskus [11]
I think the answer is water/ Liquid.

If it’s incorrect, I’m sorry
3 0
3 years ago
1. (NH)2CrO-
Alex777 [14]

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The  (NH)_2CrO is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:​

Answer:

a) Molar Mass:   155.93 Kg

b) Percent Composition of Ag:   69%

c) Percent Composition of S:  20.5%

d) Percent Composition of O:​ 10.2%

Explanation:

Molar mass =   molar mass of Ag +  molar mass of S +  molar mass of O  

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

= \frac{ \text{mass due  to Ag}}{\text {total molar mass}}  \times 100

= \frac{107.87}{155.93} \times 100

= 0.69 \times 100

= 69%

Percent Composition of S:

= \frac{ \text{mass due  to S}}{\text {total molar mass}}  \times 100

=\frac{32.06}{155.93} \times 100

= 0.205 \times 100

= 20.5%

Percent Composition of O:

= \frac{ \text{mass due  to O}}{\text {total molar mass}}  \times 100

= \frac{16.00}{155.93} \times 100

= 0.102 \times 100

= 10.2%

3 0
3 years ago
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