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Ugo [173]
3 years ago
8

Ughhh my cramps hurt sm

Engineering
2 answers:
kozerog [31]3 years ago
5 0

Answer:

Explanation:Come

tomate

vazorg [7]3 years ago
3 0

Answer:

huh? wdym?

Explanation:

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Entropy change is evaluated using Eq. 6.2a based on an internally reversible process. Can the entropy change between two states
Vadim26 [7]

Answer:

YES

Explanation:

Entropy is an extensive property of the system entropy change that value of entropy change can be determined for any process between the states whether reversible or not. i have attached the formula to calculate entropy change which is independent of whether the system is reversible or not and can be determined for any process.

4 0
4 years ago
A hypereutectoid steel often presents hard and brittle cementite along the grain boundaries of pearlite. Which of the following
Anvisha [2.4K]

Answer:

(d) Spheroidizing

Explanation:

Spheroidizing

 This is the heat treatment process for steel which having carbon percentage more than 0.8 %.As we know that a hard and brittle material is having carbon percentage more than 0.8 %.That is why this process is suitable for the hard materials.

In this process a hard and brittle materials convert into soft and ductile after this it improve the machine ability as well as improve the tool life.

In this process grain become spheroidal and these grains are ductile.

6 0
3 years ago
Select the correct answer.
andrezito [222]

Answer:

it is A. balance

Explanation:

6 0
3 years ago
In the final stages of production, a pharmaceutical is sterilized by heating it from 25 to 75°C as it moves at 0.2 m/s through a
stepan [7]

Answer:

The required heat flux = 12682.268 W/m²

Explanation:

From the given information:

The initial = 25°C

The final = 75°C

The volume of the fluid = 0.2 m/s

The diameter of the steel tube = 12.7 mm = 0.0127 m

The fluid properties for density \rho = 1000 kg/m³

The mass flow rate of the fluid can be calculated as:

m = pAV

m = \rho \dfrac{\pi}{4}D^2V

m = 1000 \times \dfrac{\pi}{4} \times ( 0.0127)^2 \times 0.2

m = 0.0253 \ kg/s

To estimate the amount of the heat by using the expression:

q = mc_p(T_{final}-T_{initial})

q = 0.0253 × 4000(75-25)

q = 101.2 (50)

q = 5060 W

Finally, the required heat of the flux is determined by using the formula:

q" = \dfrac{q}{A_s}

q" = \dfrac{q}{\pi D L}

q" = \dfrac{5060}{\pi \times 0.0127 \times 10}

q" =  12682.268 W/m²

The required heat flux = 12682.268 W/m²

3 0
3 years ago
Refrigerant-134a enters a diffuser steadily as saturated vapor at 600 kPa with a velocity of 160 m/s, and it leaves at 700 kPa a
Zina [86]

Answer:

a) V_2 = 82.1 m/s

b) m = 0.298 Kg/s

Explanation:

from A-11 to A-13 we have the following data

P_1 = 600 kpa

V_1 = 0.033925 m^3/kg

h_1 = 262.52 kJ/kg

P_2 = 700 kpa

V_2 = 0.0313 m^3/kg

T_2 = 40°C = 313K

h_2 = 278.66 kJ/kg

Now, from the conversation of mass,

A_2*V_2/u_2 = A_1*V_1/u_1

V_2 = A_1/A_2*u_2/u_1*V_1

V_2 = A_1/1.8*A_1 * 0.0313 /0.033925*160

V_2 = 82.1 m/s

now from the energy balance equation

E_in = E_out

Q_in + m(h_1 + V_1^2/2) =  m(h_2 + V_2^2/2)

m = 0.298 Kg/s

4 0
4 years ago
Read 2 more answers
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