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2 years ago

6

: A cyclical load of 1500 lb is to be exerted at the end of a 10 in. long aluminium beam (see Figure below). The bar must surviv

e for at least 10° cycles. What is the minimum diameter of the bar?

1 answer:

scZoUnD [109]2 years ago

4 0

Answer:

the minimum diameter of the bar is 1.634 in

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An electric motor is to be supported by four identical mounts. Each mount can be treated as a linear prevent problems due requir

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GIVEN:

Amplitude, A = 0.1mm

Force, F =1 N

mass of motor, m = 120 kg

operating speed, N = 720 rpm

$\frac{A}{F}$ = $\frac{0.1\times 10^{-3}}{1} = 0.1\times 10^{-3}$

Formula Used:

$A = \frac{F}{\sqrt{(K_{t} - m\omega ^{2}) +(\zeta \omega ^{2})}}$

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Let Stiffness be denoted by 'K' for each mounting, then for 4 mountings it is 4K

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$\omega = \frac{2 \pi\times N}{60}$

so,

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Damping is negligible, so, $\zeta = 0$

$\frac{A}{F}$ will give the tranfer function

Therefore,

$\frac{A}{F}$ = $\frac{1}{\sqrt{(4K - 120\ ^{2})}}$

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Answer:

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A steel bar 100 mm (4.0 in.) long and having a square cross section 20 mm (0.8 in.) on an edge is pulled intension with a load o

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Answer:

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Elastic modulus = stress ÷ strain

Load = 89,000 N

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Stress = load/area = 89,000/0.64 = 139.0625 N/in^2

Length of steel bar = 4 in

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Strain = extension/length = 4×10^-3/4 = 1×10^-3

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3 years ago