Answer:
engine B is more efficient.
Explanation:
We know that Carnot cycle is an ideal cycle for all working heat engine.In Carnot cycle there are four processes in which two are constant temperature processes and others two are isentropic process.
We also kn ow that the efficiency of Carnot cycle given as follows
![\eta =1-\dfrac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7BT_1%7D%7BT_2%7D)
Here temperature should be in Kelvin.
For engine A
![\eta =1-\dfrac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7BT_1%7D%7BT_2%7D)
![\eta =1-\dfrac{273+20}{520+273}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7B273%2B20%7D%7B520%2B273%7D)
![\eta =0.63](https://tex.z-dn.net/?f=%5Ceta%20%3D0.63)
For engine B
![\eta =1-\dfrac{T_1}{T_2}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7BT_1%7D%7BT_2%7D)
![\eta =1-\dfrac{273+20}{820+273}](https://tex.z-dn.net/?f=%5Ceta%20%3D1-%5Cdfrac%7B273%2B20%7D%7B820%2B273%7D)
![\eta =0.73](https://tex.z-dn.net/?f=%5Ceta%20%3D0.73)
So from above we can say that engine B is more efficient.
Answer:
We would need background context,
Explanation:
Then I would be happy to help!
Answer:
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main() {
string name[5];
int age[5];
int i,j;
for ( i = 0; i<=4; i++ ) {
cout << "Please enter student's name:";
cin >> name[i];
cout << "Please enter student's age:";
cin >> age[i];
}
for (i=0;i<=4;i++){
cout<<"Age of "<< name[i]<<" is "<<age[i]<<endl;
}
}
Output of above program is displayed in figure attached.
Answer:
A
Explanation:
He should get a job in engineering to see what it's like to work in the field.
It is important because now a days we all need help from engineers