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lora16 [44]
3 years ago
9

A coil having a resistance of 10 ohms and an inductance of 4 H is switched across a 20W dc source. Calculate (a) time required b

y the current to reach 50% of its final steady value, (b) value of the current after 0.5 second​
Engineering
1 answer:
Rashid [163]3 years ago
5 0

Answer:

6h

Explanation:

rt4e6

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Given the circuit at the right in which the following values are used: R1 = 20 kΩ, R2 = 12 kΩ, C = 10 µ F, and ε = 25 V. You clo
agasfer [191]

Answer:

a.) I = 7.8 × 10^-4 A

b.) V(20) = 9.3 × 10^-43 V

Explanation:

Given that the

R1 = 20 kΩ,

R2 = 12 kΩ,

C = 10 µ F, and

ε = 25 V.

R1 and R2 are in series with each other.

Let us first find the equivalent resistance R

R = R1 + R2

R = 20 + 12 = 32 kΩ

At t = 0, V = 25v

From ohms law, V = IR

Make current I the subject of formula

I = V/R

I = 25/32 × 10^3

I = 7.8 × 10^-4 A

b.) The voltage across R1 after a long time can be achieved by using the formula

V(t) = Voe^- (t/RC)

V(t) = 25e^- t/20000 × 10×10^-6

V(t) = 25e^- t/0.2

After a very long time. Let assume t = 20s. Then

V(20) = 25e^- 20/0.2

V(20) = 25e^-100

V(20) = 25 × 3.72 × 10^-44

V(20) = 9.3 × 10^-43 V

8 0
3 years ago
how to calculate the torque when a force is applied on a cog? explain the step-by-step and provide an illustration/diagram. Can
yawa3891 [41]

Explanation:

Torque is the cross product of the radius vector and force vector:

τ = r × F

In other words, it is equal to the radius times the perpendicular component of the force.

τ = r · Ftangential

If we call θ the angle between the radius and the force, then:

τ = r · F sin θ

3 0
3 years ago
I need this asap thank you :) plzzzzz When the spring on a mousetrap car is fully unwound, the force acting on the car is _____.
Usimov [2.4K]

Answer:  (only friction) the friction lets it keep its speed and not slow down and it creats volocity between the serface of where the mousecar is running and the wheels on the ground

sorry if im wrong i tried my best

6 0
2 years ago
A computer has a two-level cache. Suppose that 60% of the memory references hit on the first level cache, 35% hit on the second
Andreyy89

Answer:

t=14ns

Explanation:

We make the relation between the specific access time and the memory percentage in each level, so

60\% \Rightarrow 60/100 = 0.60\\35\% \Rightarrow 35/100 = 0.35\\05\% \Rightarrow 05/100 = 0.05

t= 0.6(5) + 0.35(5+15) + 0.05(5+15+60)\\t= 0.6(5) + 0.35(20) + 0.05(80)\\t= 3 + 7 + 4\\t= 14 ns

Average Access Time is 14 nsec.

4 0
3 years ago
3) What kind of bridges direct their load along it's curve and into the
AlladinOne [14]

Explanation:

suspension is the answer

8 0
3 years ago
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