The chemical symbol for helium is H

What is the volume of a weather balloon that has 39 grams of helium with a density 0.017 g/mL?

olchik [2.2K]

Answer:

<h3>The answer is 235.29 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question.

density = 0.017 g/mL

mass = 4 g

We have

$volume = \frac{4}{0.017} \\ = 235.2941176...$

We have the final answer as

Hope this helps you

4 0

2 years ago

The atmospheric pressure in Francisco on ascertain day was 97.6kpa what was the pressure on mmhg

vodka [1.7K]

Answer:

732.0601 mmHg

Explanation:

Given data:

Pressure = 97.6 KPa

Given pressure in mmHg = ?

Solution:

Kilo pascal and millimeter mercury both are units of pressure.

Kilo pascal is denoted as "KPa"

Millimeter mercury is denoted as " mmHg"

Kilo pascal is measure of force per unit area while also define as newton per meter square.

It is manometric unit of pressure. It is the pressure generated by column of mercury one millimeter high.

Conversation of kilopascal to mmHg:

97.6 × 7.501 = 732.0601 mmHg

3 0

3 years ago

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$

As we know that $E_{0}$ = 0.22 V and E = 0.342 V, the equation will become

$0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma$

$0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)$

$0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)$

$\frac{0.12}{0.0514}=-\ln (0.124 \gamma)$

$-2.3346=\ln (0.124 \gamma)$

$e^{-2.3346}=0.124 \gamma$

$0.0968=0.124 \gamma$

$\gamma=\frac{0.0968}{0.124}=0.78$

So, the mean activity coefficient is 0.78.

6 0

3 years ago

Determine the oxidation numbers of the elements in each compound of the following reaction. Determine what has been oxidized/red

PSYCHO15rus [73]

Answer:

<u>mnemonic</u><u> </u><u>isjdndbeudxhdnrhcurhrfkrr</u>

4 0

2 years ago

What are some examples of things you expect to see when observing a chemical reaction?

just olya [345]

Change of color, change of temperature, change in the solubility, production of gas, production of light, electricity or precipitation. Release of heat. Explosion. Production of new compounds.

7 0

3 years ago