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USPshnik [31]
3 years ago
7

A reaction is spontaneous if ΔG is ___? negative, positive, or zero?

Chemistry
1 answer:
amm18123 years ago
3 0

Answer:

A reaction is spontaneous if ΔG is negative.

Explanation:

  • The change in free energy (ΔG) is the difference between the heat released during a process and the heat released for the same process occurring in a reversible manner.

  • The sign of ΔG gives an indication for the spontaneity of the reaction:

If ΔG is negative, the reaction is spontaneous.

If ΔG = zero, the reaction is at equilibrium.

If ΔG is positive, the reaction is non-spontaneous.

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C.75%. Because the B is dominant 
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3 years ago
Vapor obtained by evaporating 0.495 grams of an unknown liquid is collected in a 127 mL flask. At 371 K, the pressure of the vap
lidiya [134]

Answer:

The molar mass in g/mol is 121.4 g/m

Explanation:

Let's apply the Ideal Gases Law to solve this:

P . V = n . R. T

V = 125 mL → 0.125L

P = 754 Torr

760 Torr ___ 1 atm

754 Torr ____ (754 / 760) = 0.992 atm

Moles = Mass / Molar mass

0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K

(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)

4.07x10⁻³ mol = 0.495 g / MM

MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m

3 0
3 years ago
Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
frozen [14]
<span>Cations mix with anions, so you know NH4+ won't mix with K+ and SO4(2-) won't miix with F-. For the reason that NH4+ and F- together have single charges, they'll mix in a 1:1 ratio, NH4F. There's two charges on SO4(2-), so it'll need two K+ to mix with, K2SO4.</span>
6 0
3 years ago
Read 2 more answers
a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what
jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in liters.

n - Molar quantity, measured in moles.

T - Temperature, measured in Kelvin.

R_{u} - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}} (2)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in liters.

T_{1}, T_{2} - Initial and final temperature, measured in Kelvin.

If we know that P_{1} = 121\,kPa, P_{2} = 202\,kPa, V_{1} = 2.7\,L, T_{1} = 288\,K and T_{2} = 303\,K, the final volume of the gas is:

V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}

V_{2} = 1.702\,L

The gas will occupy a volume of 1.702 liters.

6 0
3 years ago
All of the following are solutions except?
Vaselesa [24]

Answer:

fruit cake is the right ans

5 0
3 years ago
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