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N76 [4]
3 years ago
12

If you have a 4.6 L of gas in a piston at a pressure of 1.2 atm and compress 2p the gas until its volume is 2.6 L, what will the

new pressure inside the piston be? ​
Chemistry
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:

2.12atm

Explanation:

Boyle's Law: P1V1 = P2V2

Manipulate to solve for unknown: P2 = P1V1/V2

Substitute values:  P2=(1.2atm)(4.6L)/2.6L

P2 = 2.1230769atm

Round to 3 sig figs to get 2.12atm

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Answer:

Q = 3440Kj

Explanation:

Given data:

Mass of gold = 2kg

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Solution:

Equation

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It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg

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Arrange the molecules H2O, NH3, Ar, NaCl in order of expected increasing boiling points. 1. None of these 2. NaCl, H2O, NH3, Ar
Aleks04 [339]

Answer:

Option (4) is correct

Explanation:

  • NaCl is an ionic solid. Na^{+} and Cl^{-} ions are held together by strong coloumbic attractive force. Hence NaCl has highest boiling point'
  • Ar is a monoatomic molecule. Hence only weak london dispersion force exists between Ar atom/molecules. Hence it requires lowest amount of energy to boil and thereby possess lowest boiling point.
  • NH_{3} and H_{2}O are polar protic molecules. Hence they possess london dispersion force, dipole-dipole force and hydrogen bonding as intermolecular forces.
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