19.8 N force is tending to lift Rover vertically off the ground.
<h3>What is horizontal and vertical component?</h3>
The horizontal velocity component (
) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component (
) describes the influence of the velocity in displacing the projectile vertically.
According to the question,
The women pulls the dog with a force of 30 N at an angle of 29° from the horizontal.
Horizontal component= 30cos(29°) = 22.2 N
Vertical component = 30sin(29°) = 19.8 N
Therefore,
The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.
Hence,
19.8 N force is tending to lift Rover vertically off the ground.
Learn more about horizontal and vertical component here:
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The horizontal velocity<span> of a projectile is </span>constant<span> (a never </span>changing<span> in value), There is a </span>vertical<span>acceleration caused by gravity; its value is 9.8 m/s/s, down, The </span>vertical velocity<span> of a projectile </span>changes<span> by 9.8 m/s each second, The </span>horizontal<span> motion of a projectile is independent of its </span>vertical<span> motion.</span>
Answer:
Respuesta correcta, opción D: Es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.
Explanation:
La definición de presión es la fuerza que un cuerpo ejerce en dirección perpendicular sobre el área en la que actúa.
Cuando se aplica una fuerza sobre la superficie de un cuerpo, la presión es la siguiente:

En donde:
F es la fuerza aplicada.
A es el área del cuerpo.
Por lo tanto la opción correcta es la D: es la fuerza que un cuerpo ejerce perpendicularmente sobre el área en la que actúa.
Espero que se sea de utilidad!
Answer: 0.42 Amperes
Explanation:
Given that:
Current, I = ?
Electric charge Q = 100 coulomb
Time, T = 4.0 minutes
(The SI unit of time is seconds. so, convert 4.0 minutes to seconds)
If 1 minute = 60 seconds
4.0 minutes = 4.0 x 60 = 240 seconds
Since electric charge, Q = current x time
i.e Q = I x T
100 coulomb = I x 240 seconds
I = 100 coulomb / 240 seconds
I = 0.4167 Amperes (round to the nearest hundredth which is 0.42 amperes)
Thus, 0.42 Amperes of current flows in the circuit.
Answer:
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