d. 49.0 m/s
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The difference in frequency of the two signals is
.
The given parameters;
- <em>frequency of the 13 C signal = 201.16 MHz</em>
The energy of the 13 C signal located at 20 ppm is calculated as follows;

The energy of the 13 C signal located at 179 ppm is calculated as follows;

The difference in frequency of the two signals is calculated as follows;

Thus, the difference in frequency of the two signals is
.
Learn more here:brainly.com/question/14016376
Answer: 1.6Hz
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Answer: The taxi is moving with reference to A) Monument Circle. For each leg of the trip, the taxi's A) Average speed stays the same, but it's B) Average velocity changes.
Explanation: Brainliest Please!!!!