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3 years ago

In a river, sediment is deposited _____. on the inside bends on the outside bends by fast moving water by oxbows

1 answer:

N76 [4]3 years ago

3 0

Hey There!

Your answer is on the inside bends!

When rocks are deposition on the bottom of the river pressure can cause the rock to break down in sentiments!

If you need anymore help with your work feel free to ask me!

Hope this Helps!

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How to find the maximum amount of a substance that will dissolve using a graph?

soldi70 [24.7K]

Solubility indicates the maximum amount of a substance that can be dissolved in a solvent at a given temperature. Such a solution is called saturated. Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

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3 years ago

Which statement correctly describes why a compound is a pure substance?

ad-work [718]

Explanation:

A compound is a pure substance composed of two or more different atoms chemically bonded to one another. A compound can be destroyed by chemical means. It might be broken down into simpler compounds, into its elements or a combination of the two.

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2 years ago

What is the unit of work? * A. Joule B. Newton/meter C. Watt D. All of the above

djyliett [7]

Answer:

A! I already went through this unit. Joule.

Explanation:

3 0

3 years ago

Read 2 more answers

An ideal spring is fixed at one end. A variable force F pulls on the spring. When the magnitude of F reaches a value of 43.8 N,

maw [93]

A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant k is

43.8 N = k (0.155 m) ==> k = (43.8 N) / (0.155 m) ≈ 283 N/m

The total work done on the spring to stretch it to 15.5 cm from equilibrium is

1/2 (283 N/m) (0.155 m)² ≈ 3.39 J

The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be

1/2 (283 N/m) (0.259 m)² ≈ 9.48 J

Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.

5 0

3 years ago

A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the

Harman [31]

Answer:

The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.

F1 = T- 46, 674.656 gm/s²

Explanation:

Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.

To calculate the force caused by gravity on the basic pulley system we use the following equation:

F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g

∴ F2 = 4762.72g x 9.8 m/s²

= 46, 674.656 gm/s² or 46, 674.656 N

But since this F2 is acting in a downlowrd direction, it would be negative.

Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)

⇒ F1 = T - F2

F1 = T- 46, 674.656 gm/s²

4 0

2 years ago