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3 years ago

A third class lever has a mechanical advantage of <1. What is an example of a third class lever and why use it?

Physics

2 answers:

AVprozaik [17]3 years ago

7 0

B.) Baseball bat; increases velocity

All third class levers have a mechanical advantage less than 1. Since the output end has a longer distance from the fulcrum than the input point, the output end moves at a greater velocity than the input point. Because of this, third class levers are commonly used when trying to hit an object with as much velocity as possible.

34kurt3 years ago

5 0

<span>Baseball bat. The handle of the bat is the fulcrum. Exerting a force from the handle supplies the input force just near the middle, while the other end of the baseball bat pushes the ball with the output forces. The input force is greater than the output force but the output load is able to move farther, and this increases the ball's velocity.</span>

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A circuit supplied with 110V carries 5 Amps current. Calculate the Resistance value of the circuit?

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Answer:

The value is $R = 22 \ \Omega$

Explanation:

From the question we are told that

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Generally the resistance value is mathematically represented as

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=> $R = 22 \ \Omega$

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3 years ago

I need the solution to this

posledela

Answer:

He could jump 2.6 meters high.

Explanation:

Jumping a height of 1.3m requires a certain initial velocity v_0. It turns out that this scenario can be turned into an equivalent: if a person is dropped from a height of 1.3m in free fall, his velocity right before landing on the ground will be v_0. To answer this equivalent question, we use the kinematic equation:

$v_0 = \sqrt{2gh}=\sqrt{2\cdot 9.8\frac{m}{s^2}\cdot 1.3m}=5.0\frac{m}{s}$

With this result, we turn back to the original question on Earth: the person needs an initial velocity of 5 m/s to jump 1.3m high, on the Earth.

Now let's go to the other planet. It's smaller, half the radius, and its meadows are distinctly greener. Since its density is the same as one of the Earth, only its radius is half, we can argue that the gravitational acceleration g will be <em>half</em> of that of the Earth (you can verify this is true by writing down the Newton's formula for gravity, use volume of the sphere times density instead of the mass of the Earth, then see what happens to g when halving the radius). So, the question now becomes: from which height should the person be dropped in free fall so that his landing speed is 5 m/s ? Again, the kinematic equation comes in handy:

$v_0^2 = 2g_{1/2}h\implies \\h = \frac{v_0^2}{2g_{1/2}}=\frac{25\frac{m^2}{s^2}}{2\cdot 4.9\frac{m}{s^2}}=2.6m$

This results tells you, that on the planet X, which just half the radius of the Earth, a person will jump up to the height of 2.6 meters with same effort as on the Earth. This is exactly twice the height he jumps on Earth. It now all makes sense.

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3 years ago