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Novosadov [1.4K]

3 years ago

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1. A football team charges $30 per ticket and averages 20,000 people per game. Each

1 answer:

IRINA_888 [86]3 years ago

7 0

Question: A Football Team Charges $30 Per Ticket And Averages 20,000 People Per Game. Each Person Spends An Average Of $8 On Concessions. For Every Drop Of $1 In Price, The Attendance Rises By 800 People. What Ticket Price Should The Team Charge To Maximize Total Revenue? Calculate The TR Max.

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A football team charges $30 per ticket and averages 20,000 people per game. Each person spends an average of $8 on concessions. For every drop of $1 in price, the attendance rises by 800 people. What ticket price should the team charge to maximize total revenue? Calculate the TR max.

$50

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Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D

mr_godi [17]

Answer:

$\displaystyle g'(s) = (s-s^4)^6$

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
$\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt \right] = f(x)$

Where <em>a</em> is some constant.

We can let:
$\displaystyle g(t) = (t-t^4)^6$

By substitution:

$\displaystyle g(s) = \int_6^s g(t)\, dt$

Taking the derivative of both sides results in:
$\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]$

Hence, by the Fundamental Theorem:

$\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\ & = (s-s^4)^6\end{aligned}$

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