Answer:
0.124 m
Explanation:
the period of a simple pendulum with a small amplitude is given as
T = 2π [√(I/mgd)]
From the above stated formula,
I = moment of inertia
m = mass of the pendulum
g = acceleration due to gravity, 9.8 m/s²
d = distance from rotation axis due to center of gravity
Also, moment of Inertia, I = 2mr², if we substitute this in the above formula, we have
T = 2π [√(2mr²/mgd)]
If we assume that our r = d, then we have
T = 2π [√(2r/g)]
If we make r the subject of the formula in the above equation, we get
r = gT² / 8π²
r = (9.8 * 1²) / 8 * π²
r = 9.8 / 78.98
r = 0.124 m
Thus, the radius of the hoop is 0.124 m
<h2>================</h2><h2><em>hope it helps you see the attachment for further information.... </em></h2>
<em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em>
<h3><em>mark </em><em>it </em><em>as </em><em>brainliest</em><em>.</em><em>.</em><em>.</em><em>. </em><em>✌</em><em>✌</em></h3>
If the acceleration is constant (negative or positive) the instantaneous acceleration cannot be
Average acceleration: [final velocity - initial velocity ] /Δ time
Instantaneous acceleration = d V / dt =slope of the velocity vs t graph
If acceleration is increasing, the slope of the curve at one moment will be higher than the average acceleration.
If acceleration is decreasing, the slope of the curve at one moment will be lower than the average acceleration.
If acceleration is constant, the acceleration at any moment is the same, then only at constant accelerations, the instantaneuos acceleration is the same than the average acceleration.
Constant zero acceleration is a particular case of constant acceleration, so at constant zero acceleration the instantaneous accelerations is the same than the average acceleration: zero. But, it is not true that only at zero acceleration the instantaneous acceleration is equal than the average acceleration.
That is why the only true option and the answer is the option D. only at constant accelerations.
During the collision between two balls on the pool table there is no external force along the line of collision between them
Since there is no external force on it so here we can say
here we have
so we can say
since there is no external force so we can say during the collision the momentum of two balls will remain conserved
Answer:
19.2m/s
Explanation:
Assuming that 2.4m/s^2 was the acceleration and not a typo, we can use the equation v=at, where v=velocity, a=acceleration, and t=time,
plug in known varibles,
v=2.4*8
v=19.2m/s
