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3 years ago

Why is it important to consider the experimental error in all the empirical results presented?

Physics

2 answers:

irinina [24]3 years ago

6 0

Answer:

It is very important because scientists, especially the ones with empirical experiments and results, are prone to error and the empirical data is in need to be under strict observation done not only by many scientists but also by expermiented ones. This guards everybody to change the parameters suddenly which can affect the real results of an experiment

Explanation:

brilliants [131]3 years ago

3 0

Answer:

Explanation:

Suppose you want to know how many miles a tire gets before it must be replaced.

Suppose further that you live in a place where the roads are not very good. You would be quite concerned about how you were going to take road conditions into account.

Is rain different from snow? Will the tire get more miles in rain or snow?

Does the tire respond differently after the rain has stopped? It likely will, but how differently.

What about getting stuck especially if an alligator is the only thing looking at you being stuck and he has lunch written all over his face. Is the tire able to get you out?

All of these factors will be very important because no two seasons are alike and one July (say) of one year is not the same as another July in a different year. There has to be a way of determining what the numbers mean.

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Stress distributed over an area is best described as: a) External force b) Axial force c) Radial force d) Internal resistive for

Anit [1.1K]

Answer:

Option D is the correct answer.

Explanation:

Stress is the force per unit area that tend to change the shape of body.

Stress is defined as internal resistive force per unit area.

$\texttt{Stress}=\frac{\texttt{Internal resistive force}}{\texttt{Area}}$

$\sigma =\frac{F}{A}$

So, so stress distributed over an area is best described as internal resistive force.

Option D is the correct answer.

8 0

3 years ago

an object is placed 15.8 cm in front of a thin converging lens with an unknown focal length. if a real image forms behind the le

storchak [24]

<span>On what:

f (is the focal length of the lens) = ?
p (is the distance from the object to the lens) =15.8 cm
p' (is the distance from the image to the spherical lens) = 4.2 cm

</span><span>Using the Gaussian equation, to know where the object is situated (distance from the point).
</span>
$\frac{1}{f} = \frac{1}{p} + \frac{1}{p'}$
$\frac{1}{f} = \frac{1}{15.8} + \frac{1}{4.2}$
$\frac{1}{f} = \frac{2.1}{33.18} + \frac{7.9}{33.18}$
$\frac{1}{f} = \frac{10}{33.18}$
Product of extremes equals product of means:
$10*f = 1*33.18$
$10f = 33.18$
$f = \frac{33.18}{10}$
$\boxed{\boxed{f = 3.318\:cm}}\end{array}}\qquad\quad\checkmark$

6 0

3 years ago

A pendulum of length L is suspended from the ceiling of an elevator. When the elevator is at rest the period of the pendulum is

Juliette [100K]

Answer:

Explanation:

When the pendulum falls freely the net acceleration due to gravity is zero.

As we know that the time period of simple pendulum is inversely proportional to the square root of acceleration due to gravity, thus the time period becomes infinity.

6 0

3 years ago

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Otrada [13]

It would be 1. B 2. A 3. A

7 0

3 years ago

Does gravity increase or decrease with greater distance?

PolarNik [594]

Gravitational force decreases with increasing distance. So it decreases!

6 0

3 years ago