The answer is A. A folkway is a closely held belief by a specific group of people.
Answer:
H = 34.43 m
Explanation:
Given that,
Initial speed of the object, u = 30 m/s
The angle of projection, 
We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

So, the maximum height reached by the object is 34.43 m.
Answer:
d. )directed upward.
Explanation:
As the electron has a negative charge, when under the influence of an electric field, is subject to an electric force, which direction is the opposite to the direction of the electric field.
This is because the electric field has the same direction that the force on a positive test charge at the same point.
As the electric field points vertically downward, the electric force on the electron (a negative charge) points vertically upward.
So, the statement d. is the one that results to be true.
Answer: Satellite X has a greater period and a slower tangential speed than Satellite Y
Explanation:
According to Kepler’s Third Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.
(1)
Where;
is the Gravitational Constant
is the mass of the Earth
is the semimajor axis of the orbit each satellite describes around Earth (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
So for satellite X, the orbital period
is:
(2)
Where 
(3)
(4)
For satellite Y, the orbital period
is:
(5)
Where 
(6)
(7)
This means 
Now let's calculate the tangential speed for both satellites:
<u>For Satellite X:</u>
(8)
(9)
<u>For Satellite Y:</u>
(10)
(11)
This means 
Therefore:
Satellite X has a greater period and a slower tangential speed than Satellite Y
Answer:
3 mA.
Explanation:
The following data were obtained from the question:
Resistor (R) = 500 Ω
Potential difference (V) = 1.5 V
Current (I) =.?
Using the ohm's law equation, we can obtain the current as follow:
V = IR
1.5 = I x 500
Divide both side by 500
I = 1.5 / 500
I = 3×10¯³ A.
Therefore, the current in the circuit is 3×10¯³ A.
Finally, we shall convert 3×10¯³ A to milliampere (mA).
This can be obtained as follow:
Recall:
1 A = 1000 mA
Therefore,
3×10¯³ A = 3×10¯³ × 1000 = 3 mA
Therefore, 3×10¯³ A is equivalent to 3 mA.
Thus, the current in mA flowing through the circuit is 3 mA.