3 years ago

You run completely around a 400m track in 80s. What was your average velocity?

Physics

1 answer:

dalvyx [7]3 years ago

6 0

Answer:

V=?

S=400m

t=80s

V=S/t

V=400/80

V=5m/sec

You might be interested in

Q: What happens when cold air approaches a body of warm air? Optional Answers: A. The Warm air rises. B. The warm a

artcher [175]

A. The warm air rises! Hope this helps

8 0

3 years ago

Read 2 more answers

A iron block with a mass of 4.8 kg initially slides over a rough horizontal surface with a speed of 1.2 m/s. Friction slows the

Harlamova29_29 [7]

Answer:

Explanation:

Kinetic energy of block will be converted into heat energy by friction .

Heat energy produced = 1/2 m v²

= .5 x 4.8 x 1.2²

= 3.456 J

85% of energy is converted into heat energy , so heat energy produced

= .85 x 3.456 = 2.9376 J .

If Q heat is given to m mass of object having s as specific heat and Δt is increase in temperature

Q = msΔt

specific heat of iron s = 462 J / kg C

Putting the values ,

2.9376 = 4.8 x 462 x Δt

Δt = 13.24 x 10⁻⁴ ⁰C.

4 0

2 years ago

Two strong permanent magnets are placed one inch apart. Which two fundamental forces will most affect them?

Anuta_ua [19.1K]

The answer i got was c. gravity and strong
i hope it helps

3 0

3 years ago

A mass of 150 g stretches a spring 1.568 cm. If the mass is set in motion from its equilibrium position with a downward velocity

nadezda [96]

Answer:

$u(t)=\frac{1}{5} sin\ (25t)$

Explanation:

Given:

mass of the body stretching the spring, $m=150\ g$

extension in spring, $\Delta x=1.568\ cm$

velocity of oscillation, $u'(0)=20\ cm.s^{-1}$

initial displacement position of equilibrium, $u(0)=0$

<u>According to given:</u>

$m.g=k.\Delta x$

$150\times 980=k\times 1.568$

$k=93750\ dyne.cm^{-1}$

<u>we know frequency:</u>

$\omega=\sqrt{\frac{k}{m} }$

$\omega=\sqrt{\frac{93750}{150} }$

$\omega=25$

Now, for position of mass in oscillation:

$u= A.sin\ (\omega.t)+B.cos\ (\omega.t)$

$u= A.sin\ (25.t)+B.cos\ (25.t)$

at $t=0;\ u(0)=0\ \Rightarrow A=0$

∴ $u(t)=B.sin\ (25.t)$

∵ at $t=0;\ u'(0)=20\ cm.s^{-1}\ \Rightarrow B=\frac{1}{5}$

$u(t)=\frac{1}{5} sin\ (25t)$

7 0

3 years ago

An athlete walks 8 meters East , 2 meters South, 8 meters West, and finally 2 meters North. What is the total distance traveled?

serg [7]

Explanation:

20 meters is travelled by him

please mark me as brainliest

6 0

1 year ago

Read 2 more answers