Answer:
![\rho=1.8\times 10^{-8}\Omega.m](https://tex.z-dn.net/?f=%5Crho%3D1.8%5Ctimes%2010%5E%7B-8%7D%5COmega.m)
Explanation:
Given:
width of the wire, ![w=1.8\ mm=1.8\times 10^{-3}\ m](https://tex.z-dn.net/?f=w%3D1.8%5C%20mm%3D1.8%5Ctimes%2010%5E%7B-3%7D%5C%20m)
thickness of the flat wire, ![d=0.12\ mm=1.2\times 10^{-4}](https://tex.z-dn.net/?f=d%3D0.12%5C%20mm%3D1.2%5Ctimes%2010%5E%7B-4%7D)
length of the wire, ![l=12\ m](https://tex.z-dn.net/?f=l%3D12%5C%20m)
voltage across the wire, ![V=12\ V](https://tex.z-dn.net/?f=V%3D12%5C%20V)
current through the wire, ![I=12\ A](https://tex.z-dn.net/?f=I%3D12%5C%20A)
Now the net resistance of the wire:
using ohm's law
![R=\frac{V}{I}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BV%7D%7BI%7D)
![R=\frac{12}{12}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B12%7D%7B12%7D)
![R=1\ \Omega](https://tex.z-dn.net/?f=R%3D1%5C%20%5COmega)
We have the relation between the resistivity and the resistance as:
![R=\rho.\frac{l}{a}](https://tex.z-dn.net/?f=R%3D%5Crho.%5Cfrac%7Bl%7D%7Ba%7D)
where:
a = cross sectional area of the wire
resistivity of the wire material
![1=\rho\times \frac{12}{1.8\times 10^{-3}\times 1.2\times 10^{-4}}](https://tex.z-dn.net/?f=1%3D%5Crho%5Ctimes%20%5Cfrac%7B12%7D%7B1.8%5Ctimes%2010%5E%7B-3%7D%5Ctimes%201.2%5Ctimes%2010%5E%7B-4%7D%7D)
![\rho=1.8\times 10^{-8}\Omega.m](https://tex.z-dn.net/?f=%5Crho%3D1.8%5Ctimes%2010%5E%7B-8%7D%5COmega.m)
The power required to force the current of 4.13 A to flow through the conductor is 1927.43 watts
<h3>What is power? </h3>
This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = square current (I²)× resistancet (R)
P = I²R
<h3>How to determine the power</h3>
- Current (I) = 4.13 A
- Resistance (R) = 113 ohms
- Power (P) =?
P = I²R
P = 4.13² × 113
P = 1927.43 watts
Thus, the power required is 1927.43 watts
Learn more about electrical power:
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Answer:
5miles North
Explanation:
The displacement to the store is 5miles northward.
Displacement is the distance traveled in a specific direction. Displacement is a vector quantity.
A vector has both magnitude and direction.
The magnitude is the amount of that quantity
The direction is its orientation from a reference.
Therefore, the displacement is 5miles north
Answer:
Option D
Explanation:
When another battery is added to the circuit, the power supplied through the coil and to the magnet becomes greater leading to stronger magnetic field lines being produced.
Answer:
Explanation:
refractive index of ember = sin of angle of incidence / sin of angle of refraction
= sin 35 / sin24
= .5735 / .4067
= 1.41
This is refractive index of ember with respect to water
refractive index of ember with respect to water
= wμe = μe / μw
μe = wμe x μw
= 1.33 x 1.41
= 1.87
refractive index of ember with respect to air = 1.87 .