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Ierofanga [76]
2 years ago
10

The organelle is found in plant cells contains a green pigment and is the site of photosynthesis. this organelle is the _______

Chemistry
1 answer:
Liono4ka [1.6K]2 years ago
7 0
Answer: Chloroplasts
Reasoning: I just had my 830th lesson in school about these
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Describe how the properties of elements in the same group differ to the properties of elements in the same period
Fofino [41]

Answer:

(a) (i) All the elements of a group have similar chemical properties because they have same no. of valence electrons in their outermost shell. (ii) All the elements of a period have different chemical properties because they have different no. of valence electrons in their atoms.

5 0
3 years ago
If you have 2.1 liters of hydrogen gas (at STP), what mass of hydrogen gas would you have?
GuDViN [60]

Answer:

0.19 g

Explanation:

Step 1: Given data

Volume of hydrogen at standard temperature and pressure (STP): 2.1 L

Step 2: Calculate the moles corresponding to 2.1 L of hydrogen  at STP

At STP (273.15 K and 1 atm), 1 mole of hydrogen has a volume of 22.4 L if we treat it as an ideal gas.

2.1 L × 1 mol/22.4 L = 0.094 mol

Step 3: Calculate the mass corresponding to 0.094 moles of hydrogen

The molar mass of hydrogen is 2.02 g/mol.

0.094 mol × 2.02 g/mol = 0.19 g

6 0
3 years ago
Consider the following equilibrium: 2SO^2(g) + O2(9) = 2 SO3^(g)
saul85 [17]

Answer:

At equilibrium, the forward and backward reaction rates are equal.

The forward reaction rate would decrease if \rm O_2 is removed from the mixture. The reason is that collisions between \rm SO_2 molecules and \rm O_2\! molecules would become less frequent.

The reaction would not be at equilibrium for a while after \rm O_2 was taken out of the mixture.

Explanation:

<h3>Equilibrium</h3>

Neither the forward reaction nor the backward reaction would stop when this reversible reaction is at an equilibrium. Rather, the rate of these two reactions would become equal.

Whenever the forward reaction adds one mole of \rm SO_3\, (g) to the system, the backward reaction would have broken down the same amount of \rm SO_3\, (g)\!. So is the case for \rm SO_2\, (g) and \rm O_2\, (g).

Therefore, the concentration of each species would stay the same. There would be no macroscopic change to the mixture when it is at an an equilibrium.

<h3>Collision Theory</h3>

In the collision theory, an elementary reaction between two reactants particles takes place whenever two reactant particles collide with the correct orientation and a sufficient amount of energy.

Assume that \rm SO_2\, (g) and \rm O_2\, (g) molecules are the two particles that collide in the forward reaction. Because the collision has to be sufficiently energetic to yield \rm SO_3\, (g), only a fraction of the reactions will be fruitful.

Assume that \rm O_2\, (g) molecules were taken out while keeping the temperature of the mixture stays unchanged. The likelihood that a collision would be fruitful should stay mostly the same.

Because fewer \!\rm O_2\, (g) molecules would be present in the mixture, there would be fewer collisions (fruitful or not) between \rm SO_2\, (g) and \rm O_2\, (g)\! molecules in unit time. Even if the percentage of fruitful collisions stays the same, there would fewer fruitful collisions in unit time. It would thus appear that the forward reaction has become slower.

<h3>Equilibrium after Change</h3>

The backward reaction rate is likely going to stay the same right after \rm O_2\, (g) was taken out of the mixture without changing the temperature or pressure.

The forward and backward reaction rates used to be the same. However, right after the change, the forward reaction would become slower while the backward reaction would proceed at the same rate. Thus, the forward reaction would become slower than the backward reaction in response to the change.

Therefore, this reaction would not be at equilibrium immediately after the change.

As more and more \rm SO_3\, (g) gets converted to \rm SO_2\, (g) and \rm O_2\, (g), the backward reaction would slow down while the forward reaction would pick up speed. The mixture would once again achieve equilibrium when the two reaction rates become equal again.

5 0
3 years ago
H2(g) + Co(g) _CH3OH<br> balance the equation <br>​
Tom [10]

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

  aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

  C: 1a + 0b = 1c

  O: 1a + 0b = 1c

  H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 1

  b = 2

  c = 1

4. Substitute Coefficients and Verify Result

  CO + 2H2 = CH3OH

      L R

  C: 1 1 ✔️

  O: 1 1 ✔️

  H: 4 4 ✔️

8 0
2 years ago
The temperature of a boiling liquid can rise above its boiling point.<br> a. true<br> b. false
goldenfox [79]
The temperature of a liquid can exceed its boiling point. An example is water. Although at ordinary pressure of 1 atm, the boiling point is 100 degrees, water can still exist in higher temperatures but this time in another state. Superheated steam is the term used for water whose temperature has higher than the boiling point
5 0
3 years ago
Read 2 more answers
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