1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
5
Step-by-step explanation:
Plug n the h and j so you get 6-(2-1). Due to PEMDAS you do the parenthesis first then subtract so it become 6-1=5. ( You could use distributive property)
Answer:.36 cent
1Step-by-step explanation:1.80 divided by 5
Answer:
Angle A = 30.8
Angle B = 33.2
Step-by-step explanation:
180 - 116 = 64
This means that the other two angles need to add up to 64.
I just plugged in numbers until it worked.
I got that x = 14.6
2x + 4
2(14.6) + 4
29.2 + 4
33.2
3x - 13
3(14.6) - 13
43.8 - 13
30.8
Those are your angles. To make sure they are correct you just need to add up all the angles and make sure that they equal to 180.
116 + 33.2 + 30.8 =
180
