Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
- OM bisects AOB into angles x and x respectively
- ON bisects ∠BOC into angles y and y respectively
- OP bisects ∠COD into angles z and z respectively.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees

We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction

x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
X = 59, y = 44
2x + 18 + x - 15 = 180
3x + 3 = 180
3x = 177
x = 59
x - 15 = y
59 - 15 = y
44 = y
<span>The answer is 454. Since the value of the ones digit is 4, the last digit is a 4. Next, since the ones digit is the same as the hundreds digit, the first digit would be 4. Finally, the middle digit is the tens place and would be 5 since the tens digit is 50.</span>
Answer:
(5,5),(6,4),(-2,4) and (7,1)
Step-by-step explanation:
are concyclic