Answer:
Maximum force will be equal to 720 N
Explanation:
We have given that spring constant 
Maximum stretch of the spring x = 6 cm = 0.06 m
We have to find the maximum force on the spring
We know that spring force is given by
So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N
Answer:
11.8 m/s
Explanation:
At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).
Sum of forces in the centripetal direction:
∑F = ma
mg − N = m v²/r
At the maximum speed, the normal force is 0.
mg = m v²/r
g = v²/r
v = √(gr)
v = √(9.8 m/s² × 14.2 m)
v = 11.8 m/s
The correct answer is D. magnitude; direction
We know this thanks to Newton's 3rd law
Hope that helps!!
The pressure of the atmosphere, when a barometer reads 780 mm Hg. Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2
This problem can be solved using the formula below
P = dgh................. Equation 1
Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.
From the question,
Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,
Constant: g = 10 m/s²
Substitute these values into equation 1
P = (1.36×10⁴)(10)(0.78)
P = 10.608×10⁴ N/m²
P ≈ 1.1×10⁵ N/m²
Hence the right answer is B. 1.1×10⁵ N/m²
Learn more about Pressure here: brainly.com/question/23603188
Answer:
Ration of internal energy of hydrogen to the internal energy of helium is equal to 
Explanation:
As we know
degree of freedom of hydrogen is 5
Degree of freedom of helium is 3
Internal energy of hydrogen
Internal energy of helium
Ration of internal energy of hydrogen to the internal energy of helium is equal to
