Standard safety procedures include

bekas [8.4K]

Answer:

I dont know what to answer so im just gonna say ok

8 0

3 years ago

Brian is given an unknown element that is bright when sunlight hits it. He has a hammer and an electrical source. If he attached

ikadub [295]

Metalloids are between metals and non-metals. Metals conduct electricity while Non-metals do not. Since metalloids are somewhere in between, then the substance may conduct some electricity. Hope it helps.

4 0

3 years ago

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CHEGG 42 mT magnetic field points due west. If a proton of kinetic energy 9 x 10-12 J enters this field in an upward direction,

alexdok [17]

Answer:

The magnitude of the Force is $F = 697 *10^{-15}N$ and the direction is South

Explanation:

From the question we are told that

The magnetic field point due west and since East point toward the positive x -axis $(i)$ then this magnetic field would be mathematically represented as

$\= B = 42(-i)mT = 42*10^{-3} (-i) T$

Now from the question we are told that the kinetic energy is

$KE = 9*10^{-12}J$

Now this kinetic energy can be mathematically represented as

$KE = \frac{1}{2}mv^2$

Where m is the mass of proton which has a general value of

$m = 1.67*10^{-27}kg$

Now making the subject of the formula

$v = \sqrt{\frac{KE}{0.5 * m} }$

Substituting values we have

$v = \sqrt{\frac{9*10^{-12}}{0.5 * 1.67*10^{-27}} }$

$= 10.37*10^7m/s$

Now from the question we are told that proton is moving upward which is in the positive z direction so the velocity of the proton would be in the positive

So the velocity would be

$\= v = 10.37*10^{7} \r k \ m/s$

Now the magnetic Force can be mathematically represented as

$\= F = q \= v * \= B$

Where q is the charge on the proton which has a general value of $q =1.6*10^{-19}C$

Now substituting the value

$\= F = 1.6*10^{-19 } * (10.37 *10^7) \r k * (42 *10^{-3})(-i)$

$= 697*10^{-15} J$

Now according to Fleming's left hand rule the direction of the magnetic force is south toward the negative Y - direction $(-j)$

So the force can be denoted as

$\= F = 697*10^{-15}(-j) N$

6 0

3 years ago

Read the following story and tell me how Harper used the FITT principle. Harper works out 4-5 days a week for 60 minutes a day.

sweet [91]

Harper used the the frequency principle (F) by planning to work out 4-5 days a week. Frequency is how often you exercise, usually on a weekly basis.

She used the intensity principle (I) by deciding to exercise on a moderate level, rather than, for example, an intense workout. Intensity is basically how hard you exercise and push yourself.

She then used the time (T) principle by choosing to workout for 60 mins per day. Time meaning how much time you spend working out each day.

And lastly, she used the type (T) principle by devising a specific type and/or set of exercise(s) to do, which in her case, is drills, jogging, and weight lifting.

So all in all, Harpers frequency is 4-5 days per week, her intensity is moderate, her time is 60 mins/day, and type is basketball drills, jogging and weight lifting.

Hope I helped! :)

7 0

3 years ago

. George holds a magnet above a pile of paper clips. The paper clips move toward the magnet and stick to it before the magnet ac

mafiozo [28]

Magnetic fields surround magnets. They attract or repel, depending on the charge of the object in it.

8 0

4 years ago

Read 2 more answers