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vampirchik [111]
1 year ago
8

A neutron star is as dense as Group of answer choices water the nucleus of an atom the center of the Earth our astronomy textboo

k a white dwarf star
Physics
1 answer:
AVprozaik [17]1 year ago
4 0

A neutron star is considered as dense as the nucleus of an atom, and it represents a special type of star.

<h3>What is a neutron star?</h3>

A neutron star is a special kind of star generated after the death of a giant star that produces a supernova.

These stars (neutron stars) have a diameter really small, e.g., an area of ten kilometers in diameter.

In conclusion, a neutron star is as dense as the nucleus of an atom, and it represents a special type of star.

Learn more about neutron stars here:

brainly.com/question/14926350

#SPJ1

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A Truck with a mass of 1500 kg is decelerated At a rate of 5m/s2. how much force did this require
Marianna [84]
(1500 kg)*(5 m/s^2) = 7500 N
6 0
3 years ago
Block 1, of mass m₁ = 1.30 kg , moves along a frictionless air track with speed v₁ = 29.0 m/s. It collides with block 2, of mass
Alecsey [184]

Answer:

a. 37.7 kgm/s b. 0.94 m/s c. -528.85 J

Explanation:

a. The initial momentum of block 1 of m₁ = 1.30 kg with speed v₁ = 29.0 m/s is p₁ = m₁v₁ = 1.30 kg × 29.0 m/s = 37.7 kgm/s

The initial momentum of block 2 of m₁ = 39.0 kg with speed v₂ = 0 m/s since it is initially at rest is p₁ = m₁v₁ = 39.0 kg × 0 m/s = 0 kgm/s

So, the magnitude of the total initial momentum of the two-block system = (37.7 + 0) kgm/s = 37.7 kgm/s

b. Since the blocks stick together after the collision, their final momentum is p₂ = (m₁ + m₂)v where v is the final speed of the two-block system.

p₂ = (1.3 + 39.0)v = 40.3v

From the principle of conservation of momentum,

p₁ = p₂

37.7 kgm/s = 40.3v

v = 37.7/40.3 = 0.94 m/s

So the final velocity of the two-block system is 0.94 m/s

c. The change in kinetic energy of the two-block system is ΔK = K₂ - K₁ where K₂ = final kinetic energy of the two-block system = 1/2(m₁ + m₂)v² and K₁ = final kinetic energy of the two-block system = 1/2m₁v₁²

So, ΔK = K₂ - K₁ = 1/2(m₁ + m₂)v² - 1/2m₁v₁² = 1/2(1.3 + 39.0) × 0.94² - 1/2 × 1.3 × 29.0² = 17.805 J - 546.65 J = -528.845 J ≅ -528.85 J

7 0
3 years ago
How much voltage is required to run 0.64 A of current through a 240 resistor? Use V= IR.
SVETLANKA909090 [29]
B. If you press that into a calculator it comes up with 153.6. You then shift the decimal point 2 times forward and you end up getting 1.5 x 10^2 V.
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The value of 'g' is not affected by rotation at any place on Earth.
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Leandra is baking cookies , and they are ready to come out of the oven . Before she takes them out of the oven , she puts her mi
ch4aika [34]

Answer: Leandra puts on her mittens because if you do not you will burn your self, due to extremely high temperatures.

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