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RUDIKE [14]
3 years ago
5

A racecar driver has to hold on tightly when going around a banked curve. Approximately what is the centripetal force on a 2220.

0 kg car going around a circle with a diameter of 190.0 meters at 25.0 m/s?
Physics
1 answer:
g100num [7]3 years ago
4 0

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A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
lapo4ka [179]

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

       =9.8 \ Sin35^{\circ}

       =5.62 \ m/s^2

(b)

If friction present,

⇒ F_x=mgCos \theta

⇒ F_x=mgSin \theta-\mu_r mgCos \theta

⇒ a=gSin \theta-\mu_rgCos \theta

      =9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}

      =5.46 \ m/s^2

8 0
3 years ago
Which type of force if due to the masses of objects.
statuscvo [17]

Answer: C

Explanation: weak nuclear

7 0
2 years ago
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Someone please help me
kap26 [50]
Wait, no, its melting
6 0
3 years ago
One significant result of the Michelson experiment of 1880 was that it:
Alika [10]

Answer:

calculated the speed of light over a short distance

Explanation:

Albert Michelson <u>was an American physicist who conducted an experiment regarding the speed of light in the air 1880s.</u> He believed in the existence of "aether," a field of space that is deemed necessary for transporting electromagnetic forces. In order to do this, he setup a device in order to accurately measure the speed of light in in aether. His device is now known as <u>"Michelson interferometer." </u><em>The result was actually negative. </em>

In order to make his experiment even more accurate, he collaborated with Edward Morley, a famous American scientist. Although the result failed, together, they were able to improve and come with the a standard length of light. This calculated the speed of light over a short distance, which was the significant result of Michelson's experiment.

Thus, this explains the answer.

8 0
3 years ago
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A truck slows from a velocity of 25 m/s to a stop in 70 m. What was the truck’s acceleration
igomit [66]

v^2-u^2=2 x a x d

25^2-0^2=2 x a x 70

625-0=140 x a

625=140a

a=625/140

a=4.46 m/s^2

im not very sure but i think this is how you do this

4 0
2 years ago
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