Answer:
3
Explanation:
If oxygen reacts with iron, then both must be reactants and rust the product of that reaction
Answer:
The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.
Explanation:
![Cu (s) + 4 HNO_3 (aq) \rightarrow Cu(NO_3)_2 (aq) + 2 H_2O (l) + 2 NO_2 (g)](https://tex.z-dn.net/?f=Cu%20%28s%29%20%2B%204%20HNO_3%20%28aq%29%20%5Crightarrow%20Cu%28NO_3%29_2%20%28aq%29%20%2B%202%20H_2O%20%28l%29%20%2B%202%20NO_2%20%28g%29)
Moles of copper = ![\frac{2.01 g}{63.55 g/mol}=0.03163 mol](https://tex.z-dn.net/?f=%5Cfrac%7B2.01%20g%7D%7B63.55%20g%2Fmol%7D%3D0.03163%20mol)
According to reaction, 1 mol of copper gives 2 moles of nitrogen dioxide gas.
Then 0.03613 moles of copper will give:
of nitrogen dioxide gas
Moles of nitrogen dioxide gas = n = 0.06326 mol
Pressure of the gas = P
P = Total pressure - vapor pressure of water
P = 726 mmHg - 23.8 mmHg = 702.2 mmHg
P = 0.924 atm (1 atm = 760 mmHg)
Temperature of the gas = T = 25.0°C =298.15 K
Volume of the gas = V
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
![V=\frac{0.06326 mol\times 0.0821 atm L/mol K\times 298.15 K}{0.924 atm}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B0.06326%20mol%5Ctimes%200.0821%20atm%20L%2Fmol%20K%5Ctimes%20298.15%20K%7D%7B0.924%20atm%7D)
V = 1.68 L
The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.
Water has hydrogen bonds between Hydrogen atoms (that are slightly positive in molecules of water ) and Oxygen atoms (that are slightly negative in molecules of water), so it is necessary more energy to break them down and move water molecules from liquid state to gas.
1 mmol --------------------- 1000 <span>µmol
( mmol ) -------------------- </span> 38231 µmol
mmol = 38231*1 / 1000
mmol = 38231/ 1000
=> 38.231 mmol
<span>Add 3 x 10^9 +5.3 x 10^10
</span><span> 3 x 10^9
+5.3 x 10^10
</span>------------------
5.6 x 10^10