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3 years ago

Which gas law is represented by the following equation: P1/T1 = P2/T2

Chemistry

1 answer:

ira [324]3 years ago

4 0

Answer:

none of these

Explanation:

The expression:

P1/T1 = P2/T2 is a derivative of the combined gas law.

From the combination of the Boyle's and Charles's law, if the volume is taken to be constant, the pressure of the given mass of gas is directly proportional to the absolute temperature.

This is how the expression

P1/T1 = P2/T2 was obtained.

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shusha [124]

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Which material is the lest likely to be recognized as a mixture by looking at it under a microscope ?

Lisa [10]

Hello,

The answer is option C <span>homogeneous mixture.

Reason:

The answer is option C because you can find </span><span>homogeneous mixtures anywhere for example: Vinegar. Its not option A because suspension is usually in elements but as not a mixture. Its not option B because a colloid is a measurement tool that allows to make compounds (mixtures).Its also not option D because those type o mixtures are hard to find in extreme weather conditions.

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3 years ago

Read 2 more answers

The concentration of CI ion in a sample of H,0 is 15.0 ppm. What mass of CI ion is present in 240.0 mL of H,0, which has a densi

Doss [256]

Answer:

Mass of solute = 0.0036 g

Explanation:

Given data:

Concentration of Cl⁻ = 15.0 ppm

Volume of water = 240 mL

Mass of Cl⁻ present = ?

Solution:

1 mL = 1 g

240 mL = 240 g

Formula:

ppm = mass of solute / mass of sample ×1,000,000

by putting values,

15.0 ppm = (mass of solute / 240 g) ×1,000,000

Mass of solute = 15.0 ppm × 240 g / 1,000,000

Mass of solute = 0.0036 g

8 0

3 years ago

The half life for the decay of carbon- is years. Suppose the activity due to the radioactive decay of the carbon- in a tiny samp

EleoNora [17]

The question is incomplete. The complete question is:

The half-life for the decay of carbon-14 is 5.73x10^3 years. Suppose the activity due to the radioactive decay of the carbon-14 in a tiny sample of an artifact made of woodfrom an archeological dig is measured to be 2.8x10^3 Bq. The activity in a similiar-sized sample of fresh wood is measured to be 3.0x10^3 Bq. Calculate the age of the artifact. Round your answer to 2 significant digits.

Answer:

570 years

Explanation:

The activity of the fresh sample is taken as the initial activity of the wood sample while the activity measured at a time t is the present activity of the wood artifact. The time taken for the wood to attain its current activity can be calculated from the formula shown in the image attached. The activity at a time t must always be less than the activity of a fresh wood sample. Detailed solution is found in the image attached.

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3 years ago