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sweet-ann [11.9K]
3 years ago
8

How many formula units are in 4.56 moles of LiCl?

Chemistry
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

In 4.56 moles of LiCl 27.46*10^23 formula units is present.    

Explanation:

Formula units is defined as the empirical formula for any ionic, covalent and  network solid compounds which are used as a single unit for stoichiometric calculations. Also It can be defined as the lowest whole number ratio of ions which can be represented in an ionic compound.

We are given

4.65 moles of Lithium chloride.

One mole of Lithium chloride has 6.022*10^23 unit  Formula unit

In 4.56 moles of Lithium Chloride the formula unit will be

              = 4.56*6.022*10^23

Formula units    = 27.46 * 10^23

It is clear that in 4.56 moles of Lithium Chloride will contain 27.46*10^23 Formula unit.

Therefore in 4.56 moles of LiCl 27.46*10^23 formula units is present.    

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Reduction occurs at which electrode?
OLEGan [10]

Answer:

The electrode that removes ions from solution

Explanation:

Each electrochemical cell consists of an anode and a cathode. Oxidation occurs at the anode and reduction occurs at the cathode.

At the anode, ions move from the electrode into the solution while at the cathode ions move from the solution to the electrode.

At the cathode, metal ions accept electron(s) and become deposited on the electrode hence this electrode removes ions from solution. This is reduction.

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3 years ago
What happen when a piece of silver metal is added to the copper sulphate solution​
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Answer:

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7 0
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Read 2 more answers
Typically, a solid chloride unknown (not the AgCl product) for analysis is dried in an oven to remove absorbed water before the
tatyana61 [14]

Answer:

%Cl would be too high if not dried.

Explanation:

Cl (chlorine) is a liquid. During the process of drying AgCl, the chlorine particles evaporate and chlorine is lost.

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3 years ago
2. (Exercise 4.1.6) A liquid adhesive consists of a polymer dissolved in a solvent. The amount of polymer in the solution is imp
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800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

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3000 lb of 13% solution is required .

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Available = 500 lb of 10% solution = 50 lb of adhesive

Rest = 390 - 50 = 340 lb required .

rest mass of solution = 3000 - 500 = 2500 lb

mass of adhesive required = 340 lb

Let the mass  of 20% required be V

mass of adhesive = .20 V

.20 V = 340

V = 1700

rest of the volume = 2500 - 1700 = 800 lb which will be of pure solvent

So 800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

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How many total elements are in marble?
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