Answer:
80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.
Explanation:
Equation for the reaction:
C3H8 + 5 O2 ---------> 4 H2O + 3 CO2 + Heat
The above equation is in the presence of excess oxygen.
In this reaction,
1 mole of propane forms 4 moles of H2O
If 20 moles of propane were to be used, how many moles of water will be produced?
1 mole of propane = 4 moles of water
20 moles of propane = ( 4 * 20 ) moles of water
= 80 moles of water.
So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.
Answer:
D
Explanation:
Because 30c is kevin and add 303+30=333-30=303
Answer:
This is the tendency for particles in suspension to settle out of fluid in which they are contained and come to rest against a barrier.
Explanation:
In sedimentation, the particles are in a fluid and under the influence of forces , for example, gravitational forces, they settle and then come to rest when faced with a barrier.
The settling process is the process in which the particles fall out of liquid and sedimentation is the end of the process.
Answer:
E. Substance A will be the limiting reactant.
Explanation:
Below is a generic equation for a reaction.
2A + 3B → C + 3DA
According to the balanced equation, the theoretical molar ratio of A to B is 2:3, that is, 2 moles of A react with 3 moles of B.
<em>If I mix 2 units of A, with 6 units of B, which of the following is true?</em>
<em>A. There would be no reaction.</em> FALSE. The reaction will occur until the limiting reactant is over
<em>B. Both reactants will fully react.</em> FALSE.
<em>C. Not enough information given.</em> FALSE.
<em>D. Substance B will be the limiting reactant.</em> FALSE. Substance B will be the reactant in excess because there are 6 moles and only 3 moles are required.
<em>E. Substance A will be the limiting reactant.</em> TRUE.
