0.04350179862
Explanation:
Make sure to check for sig figs though. Basically, you have 2.54 mL and you multiply that by the 0.789 g/mL and mL cancels out and you are left with 2.00406g. There are 46.06844 grams per mol of ethanol, so to cancel out grams we multiply by 1/46.06844. And then we are left with 0.04350179862 mol
P = 2.00 atm = 2026.50hPa
T = 27°C = 300K
m = 14.0g |
Mr = 28g/mol | n = m/M = 14g/28g/mol = 0,5mol
R = 83.1 [hPa*L]/[mol*K]
pV = nRT
nRT 0,5mol * 83.1[hPa*L]/[mol*K] * 300K
V = ---------- = ----------------------------------------------------------- = <u>6.15L</u>
p 2026.5hPa
Answer B.
In an acid and base neutralization reaction, the products are salt and water.
Answer: False
Explanation: just took on edge
Answer: 36.6°C
Explanation:
Given that,
initial pressure of helium (P1) = 1.20 atm
Initial temperature (T1) = 22.0°C
Final temperature (T2) = ?
Final pressure of helium (P2) = 2.00 atm
Since pressure and temperature are given while volume is constant, apply the formula for pressure's law
P1/T1= P2/T2
1.20 atm / 22.0°C = 2.00 atm / T2
Cross multiply
1.20 atm•T2= 2.00 atm•22°C
1.20 atm•T2= 44 atm•°C
Divide both sides by 1.20 atm
1.20 atm•T2/1.20 atm = 44 atm•°C/1.20 atm
T2 = 36.6°C
