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ValentinkaMS [17]
3 years ago
11

What is the density of motor oil in g/mL if 1.25 quart (qt) weighs 2.25 pounds (lb)?

Chemistry
1 answer:
Doss [256]3 years ago
5 0

Answer:

0.86 g/mL

Explanation:

In order to solve the problem, you have to know the formula for "Density." Density refers to<em> </em><em>"mass per unit volume." </em><em>It's formula is:</em>

  • <em>Density (ρ) = </em>\frac{mass}{Volume}<em />

Next, we have to convert the units of measurement in accordance to what is being asked in the problem. It is asking for "g/mL," which means we have to convert 1.25 quarts<em> (qt.) </em>to mL and 2.25 pounds<em> (lbs.)</em> to grams.

Let's solve.

  • 1 quart = 946.35 mL

1.25 qt. x \frac{946.35 mL}{1 qt.} =<em> 1,182.94 mL</em>

  • 1 pound = 453.592 grams

2.25 pounds x \frac{453.592 grams}{1 pound} = <em>1,020.58 grams</em>

Now that we converted them to their appropriate units of measurement, we can now solve for density.

  • <em>ρ = </em>\frac{mass}{Volume}<em />
  • <em>ρ = </em>\frac{1,020.58 grams}{1,182.94 mL}<em />
  • <em>ρ = 0.86 g/mL</em>

<em>The density of the motor oil is 0.86 g/mL</em>

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Answer:

It is in the oxidation of NADH to NAD + that lactate dehydrogenase (LDH) plays an important role. LDH catalyzes the following reaction The lactate then diffuses out of the cell and the NAD + is used to continue glycolysis.It is in this manner that the cell continues to produce energy under anerobic conditions.

Explanation:

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A solution containing 1.0 M NiCl2 and 1.0 M SnBr2 undergoes electrolysis by passing a current between two platinum electrodes. W
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Answer:

Sn2+ (aq) + 2e- → Sn(s) ℰ° = -0.14 V

Explanation:

A close look at all the options shows that the most feasible first reaction is the reduction of tin II ion to ordinary metallic tin.

Given the two half cells, nickel is oxidized in one half cell to Ni II while in the second half cell, tin II ion is reduced to metallic tin. The platinum electrodes simply act as electron conduits in the cell.

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3 years ago
25 g of 116oC steam are bubbled into 0.2384 kg of water at 8oC. Find the final temperature of the system.
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Answer: The final temperature of the system will be 13.14^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of steam = 25 g

m_2 = mass of water = 0.2384 kg = 238.4 g   (1kg=1000g)

T_{final} = final temperature = ?

T_1 = temperature of steam = 116^oC

T_2 = temperature of water = 8^oC

c_1 = specific heat of steam = 1.996J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

25g\times 1.996J/g^0C\times (T_{final}-116)=-[238.4g\times 4.184J/g^0C\times (T_{final}-8)]

T_{final}=13.14^0C

Therefore, the final temperature of the system will be 13.14^0C

7 0
2 years ago
How to Balance symbol equations?
Arlecino [84]

2\; \text{Ca} + \text{O}_2 \to 2\; \text{CaO}

Try the following steps:

  1. Set the coefficient in front of the species with the greatest number of different atoms to one. In this question consider assigning Calcium Oxide \text{CaO} a coefficient of one for containing two elements.
  2. Deduce, using the rule of atomic conservation, the coefficient in front of other species. The product side of this equation contains one calcium \text{Ca} and one oxygen \text{O} atom, so should the product side. Thus assign calcium \text{Ca} a coefficient of 1 and oxygen gas a coefficient of 1/2- since 1/2 \; \text{O}_2 \times 2 \; \text{O atoms per O}_2 = 1 \; \text{O atom}: 1 \; \text{Ca} + 1/2 \; \text{O}_2 \to 1\; \text{CaO}
  3. In case any of the coefficient contains fractions, multiply all coefficients in the equation with the least common multiple of their denominators to convert the coefficients into whole numbers. In this example, multiple all coefficients by 2 to deduce the equation shown at the beginning of this answer: 2\; \text{Ca} + \text{O}_2 \to 2\; \text{CaO}.
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in descriptive scientific investigations scientis often make observations to understand the interacting parts of a complex​
masya89 [10]

The answer is System.

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Best of Luck!

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