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SOVA2 [1]
3 years ago
6

You and your housemate have an argument over the cost of the electric bill. You want to turn off the outside porch light before

going to bed each night. Your housemate wishes to keep the light on from 6:00 PM each evening to 6:00 AM the next morning and says that this will not add any significant amount to the electric bill. If the porch light bulb is a 65 W bulb, how much will your housemate's plan contribute to the electric bill each month? Take the number of days in a month as 30 and the average cost of electricity is 17.0¢/kW · h.
Physics
1 answer:
deff fn [24]3 years ago
5 0

Answer:

  Cost = $ 3,995

Explanation:

Let's start by looking for the energy consumed, which is the power over time

               E = P t

The power is 65 W, the time is 12 h each day, in a period of 30 days the time is

            t = 12  30 = 360 h

            E = 65 360

            E = 23,500 W h

We reduce to KW h

            1 kW = 1000 W

            E = 23.5 kW h

Let's use a direct ratio rule (rule of three) to find the cost

           Cost = 23.5  17.0

           Cost = 399.5 c

           Cost = $ 3,995

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Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

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Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}

k = 1.4

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inlet velocity is negligible;

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