If the carbon atom of hydrocarbon is bonded to less than 4 other atoms, the hydrocarbon is considered _______.
2 answers:
Answer : The correct option is, (D) unsaturated
Explanation :
As the organic compounds are classified into two categories which are acyclic (aliphatic) and cyclic (aromatic) compounds.
Acyclic compounds are also classified into two categories which are saturated and unsaturated compounds.
Saturated hydrocarbon : These are the compounds which containing single bonds between the carbon-carbon atoms. In saturated compounds, there are more number of hydrogen bonded with the carbon atom.
Unsaturated hydrocarbon : These are the compounds which containing double and triple bonds between the carbon-carbon atoms. In unsaturated compounds, there are less number of hydrogen bonded with the carbon atom.
Aromatic : Aromatic compounds are the type of an unsaturated compounds but it is not necessary that the unsaturated compounds are aromatic. It is a compound which containing the electrons and all the
electrons are in conjugation.
Hence, if the carbon atom of hydrocarbon is bonded to less than 4 other atoms, the hydrocarbon is considered as unsaturated.
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What is the difference between a quantity and a unit?
Answer:
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Hope this helps!!!
Answer:
37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂
Explanation:
Dilution is the reduction in concentration of a chemical in a solution. Dilution consists of lowering the amount of solute per unit volume of solution.
In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and consists of adding solvent to an existing solution. The quantity or mass of the solute is not changed but only that of the solvent.
In dilutions the expression is used:
Ci*Vi = Cf*Vf
where:
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
In this case:
- Ci: 4 M
- Vi: ?
- Cf: 0.2 M
- Vf: 750 mL
Replacing:
4 M* Vi= 0.2 M* 750 mL
Solving:
Vi= 37.5 mL
<u><em>37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂</em></u>