It's very dangerous to go that deep into the ocean due to the water pressure and the coldness, no human can physically comprehend it, so if you do end up diving that deep into the ocean, you will suffocate, crush to death, or freeze very quickly.
Answer:
Error percentage = 1.326% , 1.35% , 5.37%
density = mass / volume
For first sample:
density = 37.22/11.5 = 3.2365 g/ml
then percentage error = 100% - (3.2365/3.28 ) * 100 = 1.326%
For second sample:
density = 37.21/11.5 = 3.2356 g/ml
then percentage error = 100% - ( 3.2356 / 3.28 ) *100 = 1.35%
For third sample:
density = 37.25/12 = 3.104 g/ml
then percentage error = 100% - ( 3.104 / 3.28 ) *100 = 5.37%
Answer:
2 m/s
Explanation:
Applying the formulae of velocity,
V = d/t............. Equation 1
Where V = Velocity of the body, d = distance, t = time
From the question,
Given: d = 600 m, t = 5 minutes = (5×60) = 300 seconds.
Substitute these values into equation 1
V = 600/300
V = 2 m/s.
Hence the velocity of the body when it travels is 2 m/s
Explanation:
tbh I really don't know but
<span>83.9% is the weight percent of Al(C6H5)3 in the original 1.25 g sample.
First, look up the atomic weights of all elements involved.
Atomic weight of Aluminum = 26.981539
Atomic weight of Carbon = 12.0107
Atomic weight of Chlorine = 35.453
Atomic weight of Hydrogen = 1.00794
Now calculate the molar mass of Al(C6H5)3, and C6H6
Molar mass Al(C6H5)3 = 26.981539 + 18 * 12.0107 + 15 * 15.999
= 258.293239 g/mol
Molar mass of C6H6 = 6 * 12.0107 + 6 * 1.00794
= 78.11184 g/mol
Determine how many moles of C6H6 was produced
0.951 g / 78.11184 g/mol = 0.012174851 mol
Since the balanced formula indicates that 3 moles of C6H6 is produced for each mole of Al(C6H5)3 used, divide by 3 to get the number of moles of Al(C6H5)3 that was present.
0.012174851 mol / 3 = 0.004058284 mol
Now multiply by the molar mass of Al(C6H5)3 to get the mass of Al(C6H5)3 originally present.
0.004058284 mol * 258.293239 g/mol = 1.048227218 g
Finally, divide the mass of Al(C6H5)3 by the total mass of the original sample to get the weight percentage.
1.048227218 g / 1.25 g = 0.838582
Since all our measurements had 3 significant figures, round the result to 3 significant figures, giving 0.839 = 83.9%</span>
