True or False: The average atomic mass is always closer to the isotope with the largest mass

maxonik [38]

A volt/amp is also know as a volt ampere

4 0

4 years ago

The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th

navik [9.2K]

Answer:

(a) the input force is 36.56 N

(b) the input force is 37.49 N

Explanation:

Given;

density of hydraulic oil, ρ = 8.53 x 10² kg/m³

radius of plunger, r₁ = 0.135 m

radius of piston, r₂ = 5.43 x 10⁻³ m

Part (a) The input force needed to support 22600-N weight, when the bottom surfaces of the piston and plunger are at the same level;

$P =\frac{F}{A}$

Where;

P is pressure

F is force

A is circular area = πr²

$\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1* r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N$

Part (b) The input force needed to support 22600-N weight, when the bottom surface of the output plunger is 1.20 m above that of the input plunger

$P_2 = P_1 + \rho gh$

But, F = PA and A = πr²

$F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N$

4 0

3 years ago

A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force

nignag [31]

Answer:

Option B

Explanation:

For a system of block on inclined ramp shown in the attached image. From the attached image, the Normal force N, weight mg and frictional force f act on the block. The sum of vertical forces should be zero just as sum of vertical forces should be zero when the system is in equilibrium condition.

Taking sum of forces along the inclined plane we deduce that

[tex]f=mgsin \theta [tex]

Therefore, option B is the correct option.

8 0

3 years ago

In the study of sound, one version of the law of tensions is:

Phantasy [73]

Answer:

F1 = 80

Explanation:

f1= f2 √ (F1/F2)

Where f1 = 300, f2 = 260 and F2 = 60

Putting in the above formula

300 = 260√(F1/60)

Dividing both sides by 260

=> 1.15 = √(F1/60)

Squaring both sides

=> 1.33 = F1/60

Multiplying both sides by 60

=> F1 = 80

5 0

3 years ago

A two-point ""transfer"" gauge that can be used with an outside micrometer to measure inside diameters is called a(n):_____.

SIZIF [17.4K]

The answer is a Telescopic gauge.

A Telescopic gauge is a tow point transfer gauge that can be used with an outside micrometre to measure inside diameter.

What is Telescopic gauge?

Telescoping gauges are indirect measuring devices used to determine the internal diameter of a bore, hole, groove, slot, or other similar structure.
A handle, two telescopic rods, and a locking screw make up this T-shaped tool.
Telescopic gauges with two plunging telescopic rods are available, as are those with only one.
Telescopic gauges are used to measure the internal diameter of a bore, hole, or groove with a diameter of up to 150mm (6′′), such as camshaft bearings or connecting rod bore bearings. They are primarily used by mechanics to measure the bore size of a crankcase in an engine with moving pistons.

To learn more about Telescopic gauges visit: brainly.com/question/14006696?

#SPJ4

3 0

2 years ago