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3 years ago

13

fins the powee of a convex lens which forms a real and inverted image of magnification -1 of an object placed at a distance from

its optical centre

1 answer:

anzhelika [568]3 years ago

7 0

Explanation:

hope i am correct

hii

how are you

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A car accelerates at a rate of 6m/s^2 for 4 seconds until it has traveled a total of 40m what was the initial velocity of the ca

s344n2d4d5 [400]

Using the 2nd equation of motion;

= s = ut + ½at²

= 40 = u×2 + ½ × 6 × 2²

= 40 = 2u + 3 × 4

= 40 - 12 = 2u

= 28/2 = u

= 14 m/s = u

And its done! Simple isn't? :P

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3 years ago

Galaxy evolution is a very active area of research. Look for information on a future observatory/mission that will investigate g

Maslowich

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4 years ago

An airplane is flying through the air at a speed of 150 mph at a heading of 60 degrees. if the wind is blowing at 20 mph from th

Crazy boy [7]

Answer:

Explanation:

Given

speed of plane 150 mph

heading $60^{\circ}$

wind is blowing at 20 mph from south-east

velocity of plane w.r.t. wind

$v_{pw}=150(\cos 60\hat{i}+\sin 60\hat{j})$

$v_{w}=20(\cos 45\hat{i}-\sin 45\hat{j})$

$v_{p}=v_{pw}+v_{w}$

$v_{p}=(150\cos 60+20\cos 45)\hat{i}+(150\sin 60-20\sin 45 )\hat{j}$

$v_{p}=89.14\hat{i}+115.76\hat{j}$

$|v_{p}|=146.103 m/s$

(b)after 30 minutes

Plane traveled in x direction $=89.14\times 0.5=44.57 miles$

Plane in Y direction $=115.76\times 0.5=57.88 miles$

Total distance $=\sqrt{x^2+y^2}=73.05 miles$

direction $tan\theta =\frac{115.76}{89.14}=1.298$

$\theta =52.38^{\circ}$ w.r.t east

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3 years ago

Using what you know about newton's second law explain why a car with a lager mass use more fuel than a car with a smalle mass. a

NNADVOKAT [17]

The car with bigger Mass requires more fuel because More mass the heavier it gets. you can't grab the little car fuel tank and put it in the big car it will run out to fast.

overall answer : The bigger the mass = more weight which means it needs more fuel to run

3 0

3 years ago

"how long would it take for a ball dropped from the top of a 400-foot building to hit the ground? round your answer to two decim

Lelechka [254]

Hello

Let's convert first the height from foot to meters:
$S=400~ft=121.92~m$
This is the space covered by the ball in its accelerated motion, where the acceleration is the gravitational acceleration:
$a=g=9.81~m/s^2$
The law of motion is given by
$S= \frac{1}{2}at^2$
Re-arranging, we can get the total time of the motion:
$t= \sqrt{ \frac{2S}{a} }=4.99~s
$
which is the time the ball takes to hit the ground.

7 0

3 years ago

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