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adell [148]
2 years ago
7

First 20 element with their type ( non metal ,metal) , symbol,valency , electronic configuration , atomic number ​

Chemistry
1 answer:
Roman55 [17]2 years ago
5 0
The first 20 element have types metal non metal symbol valency electornic and etc I know it
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What is happening when there is condensation
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Name the fundamental unit involved in the derived unit joule?​
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7 0
3 years ago
1. A mixture of NaOH and Na2CO3 solution required 20.50 mL of 0.5 M HCl using
netineya [11]

Answer:

i) for NaOH (or KOH) = 13.75 mL

ii) for Na_{2}CO_{3} = 13.50 mL.

Explanation:

Phenolphthalein is an indicator which shows change in color when the conditions are highly basic.

Methyl orange is an indicator which shows change in color in presence of highly acidic medium.

For titration of NaOH and HCl we can use phenolphthalein but for sodium carbonate (a weak base) with HCl we use mehtyl orange.

Now in case of mixture of given strong base and weak base the reading or end point obtained from phenolphthalein, shows the neutralization of NaOH only and half neutralization of sodium carbonate.

NaOH+HCl--->NaCl+H_{2}O

Na_{2}CO{3}+HCl--->NaHCO_{3}+H_{2}O

While the reading or end point of methyl orange shows the neutralization of both the base present.

a) The volume of HCl used for phenolphthalein end point = 20.50 mL

Let us say the volume of HCl used for NaOH = V1

The volume of HCl used for half neutralization of sodium carbonate = V2

V1+V2 = 20.50.........(1)

b) the volume of HCl used for methyl organe end point = 27.25

This volume of HCl used for both NaOH and Na₂CO₃

V1+2V2 = 27.25  ... (2)

Equating equation 1 and 2

20.50-V2=27.25-2V2\\V2=6.75

i) Thus the volume of Acid used for NaOH (Or KOH if present in place of NaOH) = 20.50-6.75= 13.75 mL

ii) the volume of acid used for sodium carbonate =2X6.75= 13.5mL

4 0
3 years ago
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