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Ostrovityanka [42]
3 years ago
11

Silver was precipitated and collected by filtration. The experiment yielded .077g of silver after dying. The predicted yield was

.083g. The percent error present in the collection would be ?
Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
4 0

Answer:

Precentage error = 7.23%

Explanation:

The precentage error formula  is the  useful method  for determining precision of your experimental result

It can be calculated using :

percent\ error = |\frac{experimental\ value-predicted\ value} {predicted\ value}|\times 100

percent\ error = |\frac{0.077\ -0.083} {0.083}|\times 100

So we get percentage error =  7.23%

Precision means how close the experimental value to the true value or theoretical value

If percentage error is large it means experimental results are deviated and there is need to check mistakes,imprecision in the experiment

If the percentage error is zero it means the experiment is perfectly done without  inaccuracy

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URGENT <br> Best answer gets Brainliest!<br> Mg+ 2HCI ——&gt; MgCI2+ H2
avanturin [10]

Answer:

Reaction type: Single displacement

Reactant: Magnesium

Product: Dihydrogen - H2

6 0
3 years ago
Explain how carbon is conserved in the carbon cycle.
Sonja [21]

Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products

<u>Explanation</u>:

  • The carbon cycle is the procedure where carbon goes from the surrounding into living beings and to the Earth and then again goes into the air. Plants take carbon dioxide from the air and use it for food preparation. Creatures at that point eat the nourishment and carbon is put away in their bodies or discharged as CO2 through the breath.  
  • Most of the carbon is put away in sedimentary carbonates and kerogens, with the rest being spread between the sea, the air, biomass, for example, plants and creatures, and petroleum products. This is known as carbon storage.  
  • For instance, carbon, a fundamental component in natural particles, is preserved as it is moved from inorganic carbon in a biological system to natural atoms in living life forms of the biological system and back as inorganic carbon to the earth.
6 0
3 years ago
How do I pass chemistry ?
dedylja [7]

Answer:

Get good grades.

4 0
3 years ago
Androstenedione, which contains only carbon, hydrogen, and oxygen, is a steroid hormone produced in the adrenal glands and the g
Gennadij [26K]

Answer: The molecular formula for androstenedione is, C_{19}H_{26}O_2

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=5.527g

Mass of H_2O=1.548g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 5.527 g of carbon dioxide, \frac{12}{44}\times 5.527=1.507g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.548 g of water, \frac{2}{18}\times 1.548=0.172g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.893g)-[(1.507g)+(0.172g)]=0.214g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.507g}{12g/mole}=0.126moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.172g}{1g/mole}=0.172moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.214g}{16g/mole}=0.0133moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0133 moles.

For Carbon = \frac{0.126}{0.0133}=9.5

For Hydrogen  = \frac{0.172}{0.0133}=12.9\approx 13

For Oxygen  = \frac{0.0133}{0.0133}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9.5 : 13 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 19 : 26 : 2

Thus, the empirical formula for the given compound is C_{19}H_{26}O_2

The empirical formula weight of C_{19}H_{26}O_2 = 19(12) + 26(1) + 2(16) = 286 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{286.4}{286}=1

Molecular formula = C_{19}H_{26}O_2

Therefore, the molecular formula for androstenedione is, C_{19}H_{26}O_2

3 0
3 years ago
Fe2o3(s)+3co(g)→2fe(s)+3co2(g) in a reaction mixture containing 189 g fe2o3 and 63.0 g co, co is the limiting reactant. part a c
vfiekz [6]
<span>69.3 g First, determine the molar masses involved: Atomic weight iron = 55.845 Atomic weight carbon = 12.0107 Atomic weight oxygen = 15.999 Molar mass Fe2O3 = 2 * 55.845 + 3 * 15.999 = 159.687 g/mol Molar mass CO = 12.0107 + 15.999 = 28.0097 g/mol Determine how many moles of each reactant we have Moles Fe2O3 = 189 g / 159.687 g/mol = 1.18356535 mol Moles CO = 63.0 g / 28.0097 g/mol = 2.249220806 mol For every mole of Fe2O3, we need 3 moles of CO. So let's see how many moles of Fe2O3 is consumed by dividing moles CO by 3. 2.249220806 mol / 3 = 0.749740269 mol So we'll be consuming 0.749740269 moles of Fe2O3, subtract that from what we started with 1.18356535 mol - 0.749740269 mol = 0.433825081 mol Now multiply by the molar mass of Fe2O3 0.433825081 mol * 159.687 g/mol = 69.27622574 g Rounding to 3 significant figures gives 69.3 g</span>
4 0
3 years ago
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