45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)
The balanced equation for the reaction is given below:
2Al + 3Cl₂ —> 2AlCl₃
From the balanced equation above,
2 atoms of Al required 3 molecules of Cl₂.
With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:
From the balanced equation above,
2 atoms of Al required 3 molecules of Cl₂.
Therefore,
30 atoms of Al will require = 
= 45 molecules of Cl₂.
Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)
Learn more: brainly.com/question/24918379
Answer:
Total cost = $40.25 (Approx)
Explanation:
Given:
Per ounce = $1.15
Number of student = 28
Each student eat = 0.035 kg
Find:
Total cost
Computation:
Total weight of candy = 28 × 0.035 kg
Total weight of candy = 0.98 kg
1 ounce = 0.028 kg (approx).
Total weight of candy = 0.98 kg / 0.028
Total weight of candy = 35 ounce (Approx)
Total cost = 35 × $1.15
Total cost = $40.25 (Approx)
Answer:
16.499 × 10∧ 21 atoms
Explanation:
Given data:
mass of P2O5= 0.560 g
number of atoms= ?
first of all we will calculate the molar mass of P2O5:
P = 2×31 g/mol = 62 g/mol
O = 5× 16 = 80 g/mol
molar mass of P2O5 = 142 g/mol
Noe we will find the moles of 0.560 g P2O5:
moles = mass / molar mass
moles = 0.560 g/ 142 g/mol
moles = 0.0039 mol
now we will find the atoms present in 0.0039 moles:
0.0039 × 6.02 × 10∧ 23 molecules
2.357 × 10∧ 21 molecules
P2O5 consist of 7 atoms:
2.357 × 10∧ 21 × 7 = 16.499 × 10∧ 21 atoms
