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statuscvo [17]
3 years ago
14

Write the overall reaction for cellular respiration

Chemistry
1 answer:
goblinko [34]3 years ago
7 0
C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O
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If the volume and Kelvin temperature are reduced by one-half what will happen to the pressure???
jolli1 [7]

Answer:

the pressure will decrease

Explanation:

6 0
3 years ago
How many atoms are found in the products of the following chemical equation?
coldgirl [10]

There are 13 atoms in the product

<h3>Further explanation</h3>

Given

Reaction

H2SO4 + 2KOH --> K2SO4 + 2H2O

Required

The number of atoms

Solution

In a chemical equation, there are reactants on the left and products on the right

Reactants : H2SO4 + 2KOH

Products : K2SO4 + 2H2O

The number of atoms is determined by their reaction coefficient and the subscript of the atoms in the compound

K2SO4 (coefficient = 1) :

K = 2 atoms

S = 1 atom

O = 4 atoms

Total atoms = 7 atoms

2H2O(coefficient = 2) :

H = 2 x 2 = 4 atoms

O = 2 x 1 = 2 atoms

Total atoms = 6 atoms

Total = 13 atoms

5 0
2 years ago
Use the activity series below to predict the products of each of the following reactions. Do not worry about
myrzilka [38]

Answer:

i) CCl₄ and Br₂ does not react

ii) CBr₄ + Cl₂ → CCl₄ + Br₂

Explanation:

i) CCl₄ + Br₂ (no reaction)

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction

ii) CBr₄ + Cl₂

From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;

CBr₄ + Cl₂ → CCl₄ + Br₂

The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.

8 0
2 years ago
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
*What type of circuit is this in the picture?
galben [10]

Answer:

B: parallel

Explanation:

because a parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.

8 0
2 years ago
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