Answer:
The internal resistance of the cell is 0.051 ohm.
Explanation:
Given;
emf of the battery, E = 12 V
terminal voltage of the cell, V = 8.2 V
current in the circuit, I = 75 A
let the potential drop of the cell due to internal resistance (r) = Ir
The internal resistance of the cell is calculated from the equation below;
E = V + Ir
where;
r is the internal resistance of the cell
Therefore, the internal resistance of the cell is 0.051 ohm.
B: Mg+O
......................................
Answer:
and .
Explanation:
From the conservation of the mechanical energy, we have that:
Since the diver is in free fall, her initial velocity is zero. So her initial kinetic energy is also zero. Then, we get:
We will first calculate the final kinetic energy. Solving for K_f, we have:
So the kinetic energy when the diver is 1.00m above the water is 1080J.
Finally, we solve for the final potential energy U_gf:
In words, the gravitational potential energy when she is 1.00m above the water is 539J.
<span>Let L and R be the left and right vertical floor reactions
let T be the tension of the rope
summation of all forces is zero
R + L - 500 - 150- 150 = 0
R + L = 800
since the triangle formed is isosceles triangles, the legs are equal
R = L = 400 N
using the summation of the torque
L [ 4] - T[ 3 - (2 *3/5)] = 0
400 [ 4] - T[ 1.8] = 0
T = 1600/1.8
T = 889 N </span>
Answer:
The correct option is b: 30 N.
Explanation:
First, we need to find the acceleration due to gravity (a):
(1)
Where:
: is the final vertical position (obtained from the graph)
: is the initial vertical position (obtained from the graph)
v₀: is the initial speed = 0 (it is released from rest)
Δt: is the variation of time (from the graph)
From the graph, we can take the following values of height and time:
t₀ = 0 s → = 5 s
y₀ = 300 m → = 225 m
Now, by entering the above values into equation (1) and solving for "a" we have:
Finally, the weight of the object is:
Therefore, the correct option is b: 30 N.
I hope it helps you!