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Rufina [12.5K]
2 years ago
13

Explain how a compass works using scientific terminology.

Physics
2 answers:
Salsk061 [2.6K]2 years ago
8 0

Answer:

A compass works by detecting and responding to the Earth's natural magnetic fields. The Earth has an iron core that is part liquid and part solid crystal, due to gravitational pressure. It is believed that movement in the liquid outer core is what produces the Earth's magnetic field.

Explanation:

kirza4 [7]2 years ago
4 0

Answer:

The natural magnetic fields of the Earth are detected and responded to by a compass. Due to gravitational pressure, the Earth's iron core is partially liquid and partly crystallized. The Earth's magnetic field is thought to be created by movement in the liquid outer core. The Earth's magnetic field, like all other fields, has two poles: north and south. However, even though the geographic and magnetic poles are slightly offset from one another, the compass can still be an extremely useful tool for navigation, especially when declination is taken into account to account for the slight polar differences.

<em>I hope this helps you</em>

<em>:)</em>

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A major-league pitcher can throw a ball in excess of 40.1 m/s. If a ball is thrown horizontally at this speed, how much will it
mote1985 [20]

Answer:

The ball will drop 0.881 m by the time it reaches the catcher.

Explanation:

The position of the ball at time "t" is described by the position vector "r":

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

Where:

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

When the ball reaches the catcher, the position vector will be "r final" (see attached figure).

The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.

Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):

x = x0 + v0x · t

17.0 m = 0 m + 40.1 m/s · t

t = 17.0 m/ 40. 1 m/s = 0.424 s

With this time, we can calculate the y-component of the vector "r final", the drop of the ball:

y = y0 + v0y · t + 1/2 · g · t²

Initially, there is no vertical velocity, then, v0y = 0.

y = 1/2 · g · t²

y = -1/2 · 9.8 m/s² · (0.424 s)²

y = -0.881 m

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3 years ago
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