Answer:
64799.4 J
Explanation:
The following data were obtained from the question:
Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g
Specific heat capacity (C) = 0.9211 J/g°C
Initial temperature (T1) = 23°C
Final temperature (T2) = 90°C
Change in temperature (ΔT) = T2 – T1 =
90°C – 23°C = 67°C
Heat required (Q) =....?
The heat required to increase the temperature of the kettle can b obtain as follow:
Q = MCΔT
Q = 1050 x 0.9211 x 67
Q = 64799.4 J
Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.
Answer:
Time = 4.2273 seconds
Explanation:
The amount of the energy emitted by the microwave = 1100 J/s
It means that :
1100 J of the energy is emitted in 1 second
Also,
1 J of the energy is emitted in [tex]\frac {1}{1100}[tex] second
To calculate:
Time for emitting 4650 J of energy
Thus,
4650 J of the energy is emitted in [tex]\frac {1}{1100}\times 4650[tex] second
<u>Time = 4.2273 seconds</u>
Answer:examples for neutralization - treating indigestion,treatment for insect bites.hope it help you
Explanation:
Answer:- The speed of the satellite is 7.6
.
Solution:- It's a unit conversion problem that could be solved using dimensional analysis which is also known as train trail method.
The given speed of the satellite is 17000 miles per hour and we are asked to convert it to kilometers per second.
given:
1 Kilometer = 0.62 mile
1 hour = 3600 second
Let's use this given info and plug in the values to make the set up as:
= 7.616
We round the answer to two significant figures, since the given number(17000) has only two significant figures.
Hence, the speed of the satellite is 7.6 .
Answer:
0.78 atm
Explanation:
Applying general gas equation
PV/T= P'V'/T'................ Equation 1
Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
make P' the subject of the equation
P' = PVT'/TV'.............. Equation 2
From the question,
Given: P = 1.00 atm, V = 5.20 L, T = 60°C = (273+60) = 333K, V' = 6.00 L, T' = 27°C = (27+273)K = 300 K
Substitute these values into equation 2
P' = (1×5.2×300)/(333×6)
P' = 1560/1998
P' = 0.78 atm.
