Answer:
The value is 
Explanation:
From the question we are told
The pipe diameter at location 1 is 
The velocity at location 1 is 
The diameter at location 2 is 
Generally the area at location 1 is
=> 
=> 
=> 
Generally the area at location 1 is
=> 
=> 
Generally from continuity equation we have that
=> 
=>
=>
<span>The speed of the light in the materials. Hope this helps!!</span>
Given Information:
Initial speed = u = 3.21 yards/s
Acceleration = α = 1.71 yards/s²
Final speed = v = 7.54 yards/s
Required Information:
Distance = s = ?
Answer:
Distance = s = 13.61
Explanation:
We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.
We know from the equations of motion,
v² = u² + 2αs
Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.
Re-arranging the above equation for distance yields,
2αs = v² - u²
s = (v² - u²)/2α
s = (7.54² - 3.21²)/2×1.71
s = 46.55/3.42
s = 13.61 yards
Therefore, the runner traveled a distance of 13.61 yards before being tackled.
Answer:
Explanation:
From the given information:
Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:
Given that;
m_1 = 1 and
m_2 = 4
Therefore,
Making 
the subject of the formula:
=15.84
≅ 16
Hence, we can conclude that star X is more luminous by a factor of 16
