To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

Where,
B = Magnetic Field
I = Current
L = Length
<em>Note:
is a direct adaptation of the vector relation
</em>
From Newton's second law we know that the relation of Strength and weight is determined as

Where,
m = Mass
g = Gravitational Acceleration
For there to be balance the two forces must be equal therefore

Our values are given as,
Diameter 
Radius 
Magnetic Field 
From the relationship of density another way of expressing mass would be

At the same time the volume ratio for a cylinder (the shape of the wire) would be

Replacing this two expression at our first equation we have that:



Re-arrange to find I


We have for definition that the Density of copper is
, gravity acceleration is
and the values of magnetic field (B) and the radius were previously given, then:


The current is too high to be transported which would make the case not feasible.
Answer: B. the history of life in the geologic past
Explanation:
B. the history of life in the geologic past because fossils help us by telling what type of animals were alive back then ex ) a dinosaur fossil shows us what type of dinosaur it was
PLEASE MARK BRANILIEST
Answer: Bronze is a metal that can be damaged in acid rain. It is harsh to metals by almost burning them and may create rust. Everbrite is a clear, protective coating that will seal metal and bronze.
Explanation:
I know this is correct i have done all the research
The troposphere contains 80% of the the atmosphere, including the majority of gases and water vapor.
Hope it helps!
Answer:
The answer is the third photo
Explanation: