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never [62]
2 years ago
14

What volume of silver metal have a mass of 2500.0 grams?​

Physics
1 answer:
Vlada [557]2 years ago
4 0

Answer:

238 cm3

Explanation:

You take the formula for volume, V = 2500.0 g/10.5 g/cm3 = 238.095 = 238 cm3. The answer is rounded to 3 significant figures.

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A 25 MGD surface water drinking plant has four circular clarifiers (aka sedimentation basin), operated in parallel with each bas
dangina [55]

Answer:

can y

Explanation:

jj

8 0
3 years ago
A weightlifter presses a 400 n weight 0.5 m over his head in 2 seconds, what is the power of the weight lifter
Scrat [10]
There are two ways to solve this problem. First we write the given.

Given: Force F = 400 N;  Height h = 0.5 m;  Time t = 2 s

Formula: P = W/t;  but Work W = Force x distance or W = f x d
 
Weight is also a Force, therefore:  W = mg, solve for Mass m = ?

m = w/g  m = 400 N/9.8 m/s²  m = 40.82 Kg

P = W/t = F x d/t  = mgh/t  P = (40.82 Kg)(9.8 m/s²)/2 s  

P = 100 J/s or 100 Watts

3 0
3 years ago
FOR BRAINLIEST!<br><br> Does the time in the air depend on forward velocity? Explain why
Alexxx [7]

The time in air is determined by the initial vertical velocity. This is because, the steeper the launch angle the larger the vertical velocity component, that causes the launch angle to increase the time in air.

I did Physics a while ago but I believe my answer is correct. (:

Hope this helps! (:

5 0
2 years ago
If a sound is 30 dB and its absolute pressure was 66 x 10-9 Pa, what must have been the reference pressure?
Ksenya-84 [330]

Given:

I = 30dB

P = 66 × 10^{-9} Pa

Solution:

Formula used:

I = 20\log_{10}(\frac{P}{P_{o}})           (1)

where,

I = intensity of sound

P = absolute pressure

P_{o} = reference pressure

Using Eqn (1), we get:

30 = 20\log _{10}\frac{66\times 10^{-9}}{P^{o}}

P_{o} = \frac{66\times 10^{-9}}{10^{1.5}}

P_{o} = 2.08 × 10^{-9} Pa

4 0
3 years ago
A dog of mass 10 kg sits on a skateboard of mass 2 kg that is initially traveling south at 2 m/s. The dog jumps off with a veloc
Tasya [4]

Answer:

17 m/s south

Explanation:

m_1 = Mass of dog = 10 kg

m_2 = Mass of skateboard = 2 kg

v = Combined velocity = 2 m/s

u_1 = Velocity of dog = 1 m/s

u_2 = Velocity of skateboard

In this system the linear momentum is conserved

(m_1+m_2)v+m_1u_1+m_2u_2=0\\\Rightarrow u_2=-\dfrac{(m_1+m_2)v+m_1u_1}{m_2}\\\Rightarrow u_2=-\dfrac{(10+2)2+10\times 1}{2}\\\Rightarrow u_2=-17\ m/s

The velocity of the skateboard will be 17 m/s south as the north is taken as positive

3 0
3 years ago
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