1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonbull [250]
3 years ago
5

You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the t

ension in the rope to 150 N and lift the crate an additional 1.15 m. During this d motion, how much work is done on the crate by the tension force?
Physics
1 answer:
lina2011 [118]3 years ago
5 0

Answer:

W = 172.5 J

Explanation:

given,                                    

mass of the fruit crate = 14.5 kg

initial velocity to lift = 0.500 m/s

increase in the tension = 150 N

lift of crate = 1.15 m                  

work done by the tension = ?        

work done  = force x displacement

W = F s cos θ                                

θ = 0°                                    

W = F s x cos 0                                  

W = 150 x 1.15 x 1                

W = 172.5 J                                      

Work done on the crate by the tension force = W = 172.5 J

You might be interested in
Which is the largest animal<br>​
True [87]

Answer:

<em>The Antarctic blue whale </em>

Explanation:

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>A</u></em><em><u>n</u></em><em><u>t</u></em><em><u>a</u></em><em><u>r</u></em><em><u>t</u></em><em><u>i</u></em><em><u>c</u></em><em><u> </u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>e</u></em><em><u> </u></em><em><u>w</u></em><em><u>h</u></em><em><u>a</u></em><em><u>l</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>l</u></em><em><u>a</u></em><em><u>r</u></em><em><u>g</u></em><em><u>e</u></em><em><u>s</u></em><em><u>t</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>i</u></em><em><u>m</u></em><em><u>a</u></em><em><u>l</u></em><em><u> </u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>p</u></em><em><u>l</u></em><em><u>a</u></em><em><u>n</u></em><em><u>e</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u>i</u></em><em><u>g</u></em><em><u>h</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>4</u></em><em><u>0</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>p</u></em><em><u>o</u></em><em><u>u</u></em><em><u>n</u></em><em><u>d</u></em><em><u>s</u></em><em><u> </u></em><em><u>w</u></em><em><u>h</u></em><em><u>i</u></em><em><u>c</u></em><em><u>h</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>a</u></em><em><u>p</u></em><em><u>p</u></em><em><u>r</u></em><em><u>o</u></em><em><u>x</u></em><em><u>o</u></em><em><u>m</u></em><em><u>a</u></em><em><u>t</u></em><em><u>e</u></em><em><u>l</u></em><em><u>y</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u>i</u></em><em><u>g</u></em><em><u>h</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>3</u></em><em><u>3</u></em><em><u> </u></em><em><u>e</u></em><em><u>l</u></em><em><u>e</u></em><em><u>p</u></em><em><u>h</u></em><em><u>n</u></em><em><u>a</u></em><em><u>t</u></em><em><u>s</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>c</u></em><em><u>a</u></em><em><u>n</u></em><em><u> </u></em><em><u>r</u></em><em><u>e</u></em><em><u>a</u></em><em><u>c</u></em><em><u>h</u></em><em><u> </u></em><em><u>t</u></em><em><u>i</u></em><em><u>l</u></em><em><u>l</u></em><em><u> </u></em><em><u>9</u></em><em><u>8</u></em><em><u> </u></em><em><u>f</u></em><em><u>e</u></em><em><u>e</u></em><em><u>t</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>l</u></em><em><u>e</u></em><em><u>n</u></em><em><u>g</u></em><em><u>t</u></em><em><u>h</u></em><em><u>.</u></em>

5 0
2 years ago
Read 2 more answers
I need help with this problem :(​
Reil [10]

Answer:

it tells you that the speed increases until about 20 seconds then keeps a steady pace for 20 seconds then the speed drops and stops at 55 seconds in the process.

7 0
2 years ago
A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 n and is directed 20.0° above the h
steposvetlana [31]

Answer:

0.188 m/s^2

Explanation:

Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:

F_x = ma_x

where

F_x is the net force on the crate along the x-direction

m is the mass of the crate

a_x is the acceleration

Here we have:

m = 50.0 kg

F_x = F cos \theta = (10.0 N)(cos 20.0^{\circ})=9.4 N is the component of the pulling force along the horizontal direction

Solving for the acceleration,

a_x = \frac{F_x}{m}=\frac{9.4}{50.0}=0.188 m/s^2

6 0
3 years ago
Which device is using a motor?
Alexxx [7]
Out of all the options, only body massager which uses electric energy to move back and forth is using motor here. It is because a motor converts electrical energy to Mechanical energy and only massager obeys it among all the options.

In short, Your Answer would be Option C

Hope this helps!
5 0
3 years ago
Read 2 more answers
HELP MEEEE, question number 5
Kryger [21]

Answer:

Object A will get 200 & object B will get 400 Potential Energy

Explanation:

Potential Energy = mgh (mass x gravity x height)

For Object A :-

2 (mass) x 10 (approx gravity on Earth) x 10 (distance/height)

= 200

For Object B :-

4 x 10 x 10

= 400

Hence Object B will have High Potential Force than A.

Hope it helps. Thanks

6 0
2 years ago
Other questions:
  • Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is
    13·1 answer
  • The start-up procedure for a batch reactor includes a heating step where the reactor temperature is gradually heated to the nomi
    10·1 answer
  • What is the potential energy of the system composed of the three charges q1, q3, and q4, when q1 is at point R? Define the poten
    6·1 answer
  • What is the name of NASA's special plane?
    14·1 answer
  • As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near the center o
    15·1 answer
  • How are desert plants adapted to their climate?
    7·1 answer
  • What are the three types of motion
    14·1 answer
  • A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
    6·1 answer
  • 1 .
    10·1 answer
  • A woman on a bridge 100 m high sees a raft floating at a constant speed on the river below.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!