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ddd [48]
2 years ago
15

❗CORRECT ANSWER+EXPLANATION=100POINTS+BRAIBLIEST

Mathematics
2 answers:
zepelin [54]2 years ago
7 0

Answer:

Step-by-step explanation:

Factorize 12 and 75

12 = 2 * 2* 3

75 = 3 * 5 * 5

3\sqrt{12} + \sqrt{75}=3*\sqrt{2*2*3}+\sqrt{5*5*3}\\\\=3*2\sqrt{3}+5\sqrt{3}\\\\=6\sqrt{3}+5\sqrt{3}\\\\=(6+5)\sqrt{3}\\\\=11\sqrt{3}

chubhunter [2.5K]2 years ago
5 0

Answer:

Factor 12=2^{2}\times 312=2

2

×3. Rewrite the square root of the product \sqrt{2^{2}\times 3}

2

2

×3

as the product of square roots \sqrt{2^{2}}\sqrt{3}

2

2

3

. Take the square root of 2^{2}2

2

.

3\times 2\sqrt{3}+\sqrt{75}3×2

3

+

75

Step 2

Multiply 33 and 22 to get 66.

6\sqrt{3}+\sqrt{75}6

3

+

75

Hint

Multiply two factors together.

Step 3

Factor 75=5^{2}\times 375=5

2

×3. Rewrite the square root of the product \sqrt{5^{2}\times 3}

5

2

×3

as the product of square roots \sqrt{5^{2}}\sqrt{3}

5

2

3

. Take the square root of 5^{2}5

2

.

6\sqrt{3}+5\sqrt{3}6

3

+5

3

Step 4

Combine 6\sqrt{3}6

3

and 5\sqrt{3}5

3

to get 11\sqrt{3}11

3

.

11\sqrt{3}11

3

Hint

Combine like terms.

Solution

11\sqrt{3}\approx 19.05255888311

3

≈19.052558883

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