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lara [203]
2 years ago
6

Identify which statement about a solution is correct. Group of answer choices The solution has the same physical state as the ph

ysical state of the solvent. The solvent is typically the substance present in the lesser amount. Water can only be the solvent, never the solute. The solute is typically the substance present in the greater amount.
Chemistry
1 answer:
zavuch27 [327]2 years ago
5 0

Water can only be the solvent, never the solute is the statement about a solution that is correct.

  • The solute is the substance that, in general, is found in less quantity and that dissolves in the mixture.

  • The solvent, on the other hand, is the substance that usually appears in greater quantity and where the solute dissolves.

  • The most usual thing is that the solvent is the substance that establishes the physical state of the solution.

  • Water is considered a universal solvent, since it is the liquid that dissolves the most substances, a quality linked to its status as a “polar molecule”, this is due to its ability to form hydrogen bonds with other substances.

Solubility depends on the properties of a solvent that allow it to interact with a solute in a stronger way than the solvent particles do with each other.

In particular, the polar character of water makes it an excellent solvent for polar and ionic solutes, which are called hydrophilic.

Therefore, we can conclude that water can only be the solvent, never the solute is the statement about a solution that is correct.

Learn more here: brainly.com/question/2835889

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In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i
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Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: V_{1} = 21.35 mL,        M_{1} = 0.150 M

V_{2} = 25.0 mL,           M_{2} = ?

Formula used to calculate molarity of H_{2}SO_{4} is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = V_{1} + V_{2}

= 21.35 mL + 25.0 mL

= 46.36 mL  (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol

Thus, we can conclude that there are 0.006 moles of acid in the flask.

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