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Natalka [10]
3 years ago
5

Na2CO3 + 2HCl -> CO2 + H2O + 2NaCl 5.30g of NaCl was produced from 9.30g of Na2CO3. HCl was present in excess. What is the %

yield of NaCl?
Chemistry
1 answer:
Delvig [45]3 years ago
7 0

Answer:

ghello

Explanation:

lolllo

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What is the percent of copper in CuS?
bonufazy [111]

Answer:

Element Symbol Mass Percent

Cuprum Cu 66.464%

Sulfur S 33.537%

Explanation:

I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!

7 0
2 years ago
Is sulfur a metal, nonmetal, metalloid, or noble gas?
Blababa [14]
Sulfer is a nonmetal
6 0
2 years ago
What is the final, balanced equation that is formed by combining these two half reactions?
lara31 [8.8K]

Answer: Balanced equation that is formed by combining these two half reactions is Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O.

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, Cu \rightarrow Cu^{2+} + 2e^{-}

NO^{-}_{3} + 2e^{-} + 2H^{+} \rightarrow NO^{-}_{2} + H_{2}O

On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.

Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O

Thus, we can conclude that balanced equation that is formed by combining these two half reactions is Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O.

7 0
3 years ago
Which number represents an acidic pH, 4 or 9?
Leno4ka [110]

Answer:

pH 4 represents an acidic

5 0
3 years ago
Reacting 35.4 ml of 0.220 m agno3 with 52.0 ml of 0.420 m k2cro4 results in what mass of solid formed
laila [671]
Answer is: 1.29 grams <span>of solid formed.
</span>Chemical reaction: 2AgNO₃(aq) + K₂CrO₄(aq) → Ag₂CrO₄(s) + 2KNO₃(aq).
n(AgNO₃) = c(AgNO₃) · V(AgNO₃).
n(AgNO₃) = 0.220 M · 0.0351 L.
n(AgNO₃) = 0.0078 mol; limiting reactant.
n(K₂CrO₄) = 0.420 M · 0.052 L.
n(K₂CrO₄) = 0.022 mol.
From chemical reaction: n(AgNO₃) : n(Ag₂CrO₄) = 2 : 1.
n(Ag₂CrO₄) = 0.0078 mol ÷ 2.
n(Ag₂CrO₄) = 0.0039 mol.
m(Ag₂CrO₄) = 0.0039 mol · 331.73 g/mol.
m(Ag₂CrO₄) = 1.29 g.

7 0
2 years ago
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