Na2CO3 + 2HCl -> CO2 + H2O + 2NaCl 5.30g of NaCl was produced from 9.30g of Na2CO3. HCl was present in excess. What is the %
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The concentration of the solution reduces and the number of moles of solute isn't affected.
Data;
- V1 = 50mL
- C1 = 12.0M
- V2 = 200mL
- C2 = ?
1. When the solution is diluted, the concentration changes and this time, the concentration reduces.
Using dilution formula
The concentration of the solution reduces.
2. The number of moles remains the same.
When a solution is diluted, the number of moles remains the same because there's no change in the mass of the solute.
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