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Natalka [10]
3 years ago
5

Na2CO3 + 2HCl -> CO2 + H2O + 2NaCl 5.30g of NaCl was produced from 9.30g of Na2CO3. HCl was present in excess. What is the %

yield of NaCl?
Chemistry
1 answer:
Delvig [45]3 years ago
7 0

Answer:

ghello

Explanation:

lolllo

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The reaction for the combustion of methane can be expressed as follows.
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We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
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Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
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