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sasho [114]
3 years ago
12

How many moles are in 987 grams of Ra(OH)2

Chemistry
2 answers:
ra1l [238]3 years ago
7 0
Molar mass Ra(OH)2 = 260 g/mol 
<span>Moles = 987 g / 260 = 3.80 moles</span>
Ket [755]3 years ago
5 0

Answer:

3.84mol

Explanation:

How many moles are in 987 grams of Ra(OH)2

the elements in the compound are as follows

radium

oxygen

and hydrogen

to get the the mole, we say the ratio of mass of the compound to the molecular mass(g/mol)

molecular mass= 223 + 16 * 2 + 1 * 2 =257 g/mol

mass=987g is defined as the quantity of matter in a body

mol=987/257

mol=3.84mol

mol has to do with the amount of a substance.

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1. Describe what an irreversible change is.
lozanna [386]

Answer:

A change is called irreversible if it cannot be changed back again. In an irreversible change, new materials are always formed.

Explanation:

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In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be p2o5. experimentation shows
agasfer [191]
The empirical formula for the compound is - P₂O₅
the empirical formula is the simplest ratio of whole numbers of components in a compound.
molecular formula is the actual ratio of components in a compound.
we have to first find the number of empirical units in the molecular formula 
molecular mass - 283.89 g/mol
mass of empirical formula - 283.8 g
number of empirical units - 283.89 g/mol / 283.8 g
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3 0
3 years ago
The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for
tester [92]

The given question is incomplete. The complete question is:

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:

A. K(s)+O_2(g)\rightarrow KO_2(s)

B. CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)

C. CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

D. N_2O_2(g)\rightarrow 2NO(g)+O_2(g)

Answer: A. K(s)+O_2(g)\rightarrow KO_2(s) : decreases

B. CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2(g) : decreases

C. CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g): no change

D. N_2O_2(g)\rightarrow 2NO(g)+O_2(g) : increases

Explanation:

Entropy is defined as the randomness of the system.

Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.

In reaction K(s)+O_2(g)\rightarrow KO_2(s), as gaseous reactant is changed to solid product, entropy decreases.

In reaction CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g), as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.

In reaction CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g), as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.

In reaction  N_2O_2(g)\rightarrow 2NO(g)+O_2(g) , as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.

7 0
3 years ago
I need help with this answer
frez [133]
A
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Which is the correct formula for phosphorus pentachloride?
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PCl5

hope this helps

have a wonderful day

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