How many moles are in 987 grams of Ra(OH)2

Chemistry

2 answers:

ra1l [238]3 years ago

7 0

Molar mass Ra(OH)2 = 260 g/mol
<span>Moles = 987 g / 260 = 3.80 moles</span>

Ket [755]3 years ago

5 0

Answer:

3.84mol

Explanation:

How many moles are in 987 grams of Ra(OH)2

the elements in the compound are as follows

radium

oxygen

and hydrogen

to get the the mole, we say the ratio of mass of the compound to the molecular mass(g/mol)

molecular mass= 223 + 16 * 2 + 1 * 2 =257 g/mol

mass=987g is defined as the quantity of matter in a body

mol=987/257

mol=3.84mol

mol has to do with the amount of a substance.

You might be interested in

The proportion of dissolved substances in seawater is usually expressed in

LiRa [457]

Answer:

The proportion of dissolved substances in seawater is usually expressed in ppm, ppb or ppt

Explanation:

The concentration of very diluted solutions should be expressed in parts per million, billion or trillion.

ppm = mass from the solute . 10⁶ / mass or volume of the solution

ppb = mass from the solute . 10⁹ / mass or volume of the solution

ppt = mass from the solute . 10¹² / mass or volume of the solution

ppm = mg/kg, μg/g, μg/mL → These are the units

ppb = ng/g

ppt = pg/g

3 0

3 years ago

PLEASE HELP ME WITH PHYSICAL SCIENCE!! PRETTY EASY QUESTION

Umnica [9.8K]

Explanation:

Bbbbbbbbbbbbbbbbbbbbb

7 0

3 years ago

Read 2 more answers

Does potassium nitrate (KN03) incorporate ionic bonding, covalent bonding, or both? Explain.

ladessa [460]

Answer: $KNO_3$ incorporates both ionic bonding and covalent bonding.

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here potassium is having an oxidation state of +1 called as $K^{+}$ cation and nitrate $NO_3^{-}$ is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $KNO_3$ . $NO_3^-$ is formed by sharing of electrons between two non metals nitrogen and oxygen.